The price of a staff ticket and the price of a student ticket is $8 and $14
Given:
Day 1:
Number of staff tickets sold = 3
Number of students tickets sold = 1
Total revenue day 1 = $38
Day 2:
<em>Number of staff tickets sold</em> = 3
<em>Number of students tickets sold</em> = 2
<em>Total revenue day</em> 2 = $52
let
<em>cost of staff tickets</em> = x
<em>cost of students tickets</em> = y
The equation:
<em>3x + y = 38 (1)</em>
<em>3x + y = 38 (1)3x + 2y = 52 (2)</em>
subtract (1) from (2)
2y - y = 52 - 38
y = 14
substitute y = 14 into (1)
3x + y = 38 (1)
3x + 14 = 38
3x = 38 - 14
3x = 24
x = 24/3
x = 8
Therefore,
cost of staff tickets = x
= $8
cost of students tickets = y
= $14
Read more:
brainly.com/question/22940808
Answer:
B) 30
Step-by-step explanation:
bottom of graph represents number of tickets, look for 6 then go up till you hit the dot now go to the other side of the graph ( costs) and see which number the line hit which is 30
So 9:30 17 min goes by so its 9:47 but tim arrived 8 mins before so it was 9:39 when he arrived. Next tyson arrived 20 min after tims ORIGINAL oppt 9:47 20 min 10:07 then for marks 35 min after witch is 10:12
Hello from MrBillDoesMath!
Answer:
Choice A, 18x - 6y = 20
Discussion:
Given line
-9x + 3y = 12 (M)
Choice A:
18x - 6y = 20 => divide both sides by -2
-9x + 3y = -10 (N)
The left hand sides of (M) and (N) are equal implying that right hand sides are equal which further implies 12 = -10. Contradiction! so the system M and N has no solution.
Thank you,
MrB
Answer: x = 5
Explanation:
2(5x + 2) = 54
10x + 4 = 54
10x = 54 - 4
10x = 50
x = 50/10
x = 5
Therefore, x = 5
