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3 years ago

4 3/5 times 7 expain

1 answer:

7 0

Convert the mixed number into a fraction. To do this, multiply the denominator by the whole number, and add the numerator. 5*4+3=23. Then put that over the denominator.

So we now have 23/5 * 7. To multiply fractions, multiply the numerators together and the denominators together.

(23*7)/5 = 161/5 or 32.2

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The number of girls who work at Super Shopper is 4 more than 2 times the number of boys. If 30 boys work at Super Shopper, how m

Oxana [17]

Answer:

I'm pretty sure it's 92!

7 0

2 years ago

In the Volume of Cylinders, Cones and Spheres section, what is the volume of a sphere with a radius of 6in? *

Rudiy27

Answer:

The volume of the sphere is 288π in³

Step-by-step explanation:

To calculate the volume of a sphere we have to use the following formula:

V = volume

r = radius

V = ⁴⁄₃πr³

V = ⁴⁄₃ * π * (6in)³

V = π * ⁴⁄₃ * 216 in³

V = 288π in³

The volume of the sphere is 288π in³

4 0

3 years ago

26. Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics

hjlf

The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics course.

Then they are given a post-test once the professor has concluded lecturing on the material.

Pre-test and post-test scores for 4 students in an elementary statistics class are given below.

Then we have

$\mu _d = \mu _{post} - \mu _{pre}$

Then the null hypotheses and alternative hypotheses will be

H₀: $\mu _d = 0$

Hₐ: $\mu _d > 0$

Then the test statistic will be

$\rm \overline{x} _d = \dfrac{\Sigma x_d}{n} = \dfrac{15+12+10+1}{4}\\\\\overline{x} _d = 9.5$

Then

$\rm S_d = 6.02$

The test statistic value is given by

$\rm t = \dfrac{\overline{x} _d }{\dfrac{S_d}{\sqrtn}} \\\\t = \dfrac{9.5}{\dfrac{6.02}{\sqrt4}}\\\\t = 3.16$

Since this is a right-tailed test, so the critical value is given by

$\rm t_{n-1}(\alpha ) = t_3 (0.05) = 2.353$

Since the test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

Hence, we can conclude that $\mu _d > 0$ that is test scores have improved.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

#SPJ1

7 0

2 years ago

How do I graph the solution

notsponge [240]

Make the circle closed and the > needs to be underlined