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nikklg [1K]
3 years ago
12

4 3/5 times 7 expain

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
7 0
Convert the mixed number into a fraction. To do this, multiply the denominator by the whole number, and add the numerator. 5*4+3=23. Then put that over the denominator.

So we now have 23/5 * 7. To multiply fractions, multiply the numerators together and the denominators together.

(23*7)/5 = 161/5 or 32.2
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The number of girls who work at Super Shopper is 4 more than 2 times the number of boys. If 30 boys work at Super Shopper, how m
Oxana [17]

Answer:

I'm pretty sure it's 92!

7 0
2 years ago
In the Volume of Cylinders, Cones and Spheres section, what is the volume of a sphere with a radius of 6in? *
Rudiy27

Answer:

The volume of the sphere is 288π in³

Step-by-step explanation:

To calculate the volume of a sphere we have to use the following formula:

V = volume

r = radius

V = ⁴⁄₃πr³

V = ⁴⁄₃ * π * (6in)³

V = π * ⁴⁄₃ * 216 in³

V = 288π in³

The volume of the sphere is 288π in³

4 0
3 years ago
26. Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics
hjlf

The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics course.

Then they are given a post-test once the professor has concluded lecturing on the material.

Pre-test and post-test scores for 4 students in an elementary statistics class are given below.

Then we have

\mu _d = \mu _{post} - \mu _{pre}

Then the null hypotheses and alternative hypotheses will be

H₀: \mu _d = 0

Hₐ: \mu _d > 0

Then the test statistic will be

\rm \overline{x} _d = \dfrac{\Sigma x_d}{n} = \dfrac{15+12+10+1}{4}\\\\\overline{x} _d = 9.5

Then

\rm S_d = 6.02

The test statistic value is given by

\rm t = \dfrac{\overline{x} _d }{\dfrac{S_d}{\sqrtn}} \\\\t = \dfrac{9.5}{\dfrac{6.02}{\sqrt4}}\\\\t = 3.16

Since this is a right-tailed test, so the critical value is given by

\rm t_{n-1}(\alpha ) = t_3 (0.05) = 2.353

Since the test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

Hence, we can conclude that \mu _d > 0 that is test scores have improved.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

#SPJ1

7 0
2 years ago
How do I graph the solution
notsponge [240]
Make the circle closed and the > needs to be underlined

8 0
3 years ago
Find the power of 1.4 product is 3.<br><br><br>1.64<br><br>2.744<br><br>4.2<br><br>1.96
Natasha2012 [34]

Answer:

the answer would be 4.2

5 0
2 years ago
Read 2 more answers
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