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3 years ago

Label the different components to the atom below. (you should only use each term once)

Chemistry

1 answer:

Darya [45]3 years ago

3 0

Answer:

do you know the answer to it

Explanation:

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How would copper become copper (+2)

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Its because its copper?

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3 years ago

Which of the following best describes how water evaporates? *

Evgesh-ka [11]

The answer is A because water can only evaporate if a liquid substances becomes gas , in this case it’s the water. When water is heated it evaporates. The molecule moves and vibrates so quickly that they can move to the atmosphere

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3 years ago

18. Which one of the following is generally NOT true about elements in the

Dennis_Churaev [7]

Answer:

Statement B "Elements at the right side of the period are smaller in size" is not true.

Explanation:

Going through the rows of the elements in the period the size of the elements get continuously bigger.

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3 years ago

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What is the function of sulphur (IV) oxide in the reaction represented by the following equation? SO 2(aq) + 2H2S(g) -> 35 (s

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<h3>Oxidising Agent</h3>

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3 years ago

The rapid decomposition of sodium azide, NaN3, to its elements is one of the reactions used to inflate airbags: 2 NaN3 (s)  2 N

masha68 [24]

<u>Answer:</u> The amount of nitrogen gas produced is 3.864 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of $NaN_3$ = 6.00 g

Molar mass of $NaN_3$ = 65 g/mol

Putting values in equation 1, we get:

$\text{Moles of }NaN_3=\frac{6.00g}{65g/mol}=0.092mol$

For the given chemical reaction:

$2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)$

By Stoichiometry of the reaction:

2 moles of $NaN_3$ produces 3 moles of nitrogen gas

So, 0.092 moles of $NaN_3$ will produce = $\frac{3}{2}\times 0.092=0.138mol$ of nitrogen gas

Now, calculating the mass of nitrogen gas by using equation 1, we get:

Molar mass of nitrogen gas = 28 g/mol

Moles of nitrogen gas = 0.138 moles

Putting values in equation 1, we get:

$0.138mol=\frac{\text{Mass of nitrogen gas}}{28g/mol}\\\\\text{Mass of nitrogen gas}=(0.138mol\times 28g/mol)=3.864g$

Hence, the amount of nitrogen gas produced is 3.864 grams

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3 years ago