Answer:
0.0165 (L) * 0.750 (mol/L) = 0.0124 mol NaOH in 16.5 mL
Explanation:
Answer:
I think it's B
Explanation:
apologies if I get this wrong
Answer:
12.1% C, 16.1% O, 71.8% Cl
Explanation:
i hope this is correct
Answer:
c. chloroacetate ion
Explanation:
The chloroacetic acid, ClCH₂CO₂H, is a weak acid with Ka = 1.36x10⁻³. When this weak acid is in solution with its conjugate base, ClCH₂CO₂⁻ (From sodium chloroacetate) a buffer is produced. The addition of a strong acid as the HCl produce the following reaction
HCl + ClCH₂CO₂⁻ → ClCH₂CO₂H + Cl⁻.
Where the acid reacts with the chloroacetate ion to produce more chloroacetic acid
That means, the HCl reacts with the chloroacetate ion present in the buffer solution
Right answer is:
<h3>c. chloroacetate ion</h3>
B)
<span>
a subatomic particle with no electric charge, found in the nucleus of an atom </span>
