2 years ago

Electronic configuration of the element aluminum

Chemistry

1 answer:

Bad White [126]2 years ago

4 0

The answer is [Ne] 3s2 3p1

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At 500 K the reaction 2 NO(g) + Cl2(g) ⇌ 2 NOCl(g) has Kp = 51 In an equilibrium mixture at 500 K, the partial pressure of NO is

Aleks [24]

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p3=0.36atm (partial pressure of NOCl)

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2 NO(g) + Cl2(g) ⇌ 2 NOCl(g) Kp = 51

lets assume the partial pressure of NO,Cl2 , and NOCl at eequilibrium are P1 , P2,and P3 respectively

$Kp=\frac{[NOCl]^{2} }{[NO]^{2} [Cl_2] }$

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