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3 years ago

How much heat, in joules, is required to raise the temperature of 1.82 Kg of water by 3.32°C

Chemistry

1 answer:

IrinaK [193]3 years ago

6 0

Answer:

2.1 x 10^6 J

Explanation:

Long story short, just think of the units of every question and then think again which unit needs to be cancelled out inorder for you to get the one which is asked.

the formula to calculate heat energy is Q = mcT

T - change in temperature

m - mass of substance

c - specific heat capacity of substance

the change in temperature is already given but you will need to change it to kelvin inorder for it to get cancelled out with the unit under specific heat capacity which is J/k gram. Tk = Tc + 273 = 3.32 + 273.15 = 276.47K

now keep in mind that c varies from substance to substance.

in this case it is 4.18J/k.g for water.

you will also need to convert the mass from kilograms to grams so it can cancel out as well. so now let's multiply 1.82 kg by a 1000 so that we can convert it to grams. which is equivalent to 1820g

now it's all set...let's substitute the values we dag out in the Heat formula Q = mcT

=1820g x 4.18Jk.g x 276.47K = 2.1 x 10^6J

so this is out final answer for heat required to raise the temperature of water by the particularly given quantity.

peace to you.

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A. In the complete reaction of 22.99 g of sodium

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<h3>Further explanation</h3>

The reaction

$\tt Na+Cl\Rightarrow NaCl$

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Na : Cl : NaCl = 1 : 1 : 1

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mol of Cl :

$\tt mol=\dfrac{35.45}{35.45}=1$

Then the reactants are completed reacting because it matches the mole ratio, which is 1: 1

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