Answer:
23430.4 J.
Explanation:
From the question given above, the following data were obtained:
Mass (M) = 70 g
Initial temperature (T₁) = 10 °C
Final temperature (T₂) = 90 °C
Specific heat capacity (C) = 4.184 J/gºC
Heat (Q) required =?
Next, we shall determine the change in the temperature of water. This can be obtained as follow:
Initial temperature (T₁) = 10 °C
Final temperature (T₂) = 90 °C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 90 – 10
ΔT = 80 °C
Finally, we shall determine the heat energy required to heat up the water. This can be obtained as follow:
Mass (M) = 70 g
Change in temperature (ΔT) = 80 °C
Specific heat capacity (C) = 4.184 J/gºC
Heat (Q) required =?
Q = MCΔT
Q = 70 × 4.184 × 80
Q = 23430.4 J
Therefore, 23430.4 J of heat energy is required to heat up the water.
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Use this formula mass = moles x molar mass.
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