The maximum height the ball achieves before landing is 682.276 meters at t = 0.
<h3>What are maxima and minima?</h3>
Maxima and minima of a function are the extreme within the range, in other words, the maximum value of a function at a certain point is called maxima and the minimum value of a function at a certain point is called minima.
We have a function:
h(t) = -4.9t² + 682.276
Which represents the ball's height h at time t seconds.
To find the maximum height first find the first derivative of the function and equate it to zero
h'(t) = -9.8t = 0
t = 0
Find second derivative:
h''(t) = -9.8
At t = 0; h''(0) < 0 which means at t = 0 the function will be maximum.
Maximum height at t = 0:
h(0) = 682.276 meters
Thus, the maximum height the ball achieves before landing is 682.276 meters at t = 0.
Learn more about the maxima and minima here:
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Answer:
0
Step-by-step explanation:
The slope of the line is 0 as it is parallel to x-axis.
Slope = (y2 - y1)/(x2 - x1)
= (2-2)/(4-(-2))
= 0
<h3>
Answer:</h3>
The slope is
and the y-intercept is
.
<h3>
Explanation:</h3>
This function is written in slope-intercept form, which is
. In this form,
is the slope and
is the y-intercept.
In this case,
and
, so those are the answers to this problem.
each one gets 2 and their will be 4 slices left
The correct answer is the fourth one 324\pi cm3