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Step2247 [10]
2 years ago
11

City planners are planning to build a new community pool. They agree that the pool will be rectangular in shape, but the propose

d dimensions changed. At the most recent meeting, it was determined that the width would remain at 11.6 meters but that the length would increase by 3.7 meters. So, the pool would now cover an area of 205.85 square meters.
Which equation can be used to determine the original length of the pool, l?


205.85=2(l+15.3)

205.85=11.6(l+3.7)

205.85=3.7(l+11.6)
Mathematics
1 answer:
kobusy [5.1K]2 years ago
6 0

The equation that can be used to determine the original length of the pool is 205.85 = 11.6(l + 3.7)

Let l be the original length of the pool.

Since the length of the pool is increased by 3.7 m, the new length L = l + 3.7.

Also, the area of the pool A = 205.85 square meter and it is a rectangle with width, W = 11.6 meters,

So, A = LW

Substituting the values of the variables into the equation, we have

A = LW

205.85 = (l + 3.7)11.6

So, the equation that can be used to determine the original length of the pool is 205.85 = 11.6(l + 3.7)

Learn more:

brainly.com/question/12932084

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mrs_skeptik [129]

Answer  

Given

Sean's house is currently worth $188,900.

According to a realtor, house prices in Sean's neighborhood will increase by 4.8% every year.

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Formula

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As given

Take\ Principle\ = P_{0}

Rate = \frac{4.8}{100}

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Compound\quaterly\ interest = P_{0}(1 + \frac{0.048}{4})^{4t}

Compound\quaterly\ interest = P_{0} (1 + \frac{0.048}{4})^{4t}

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Now also calculated monthly.

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Compound\ monthly = Principle (1 + \frac{r}{12})^{12t}

As given

Take\ Principle\ = P_{0}

Rate = \frac{4.8}{100}

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Compound\ monthly = P_{0} (1 + \frac{0.048}{12})^{12t}

Compound\ monthly = P_{0} (1 + 0.004)^{12t}

Compound\ monthly = P_{0} (1.004)^{12t}

As the approximation quarterly growth rate of the value of sean's house is near the Compounded quarterly interest .

Thus Option (A) is correct.

i.e

The expression (1.0118)^{4t} reveals the approximate quarterly growth rate of the value of Sean's house.




                                               

                                                       




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