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Step2247 [10]
2 years ago
11

City planners are planning to build a new community pool. They agree that the pool will be rectangular in shape, but the propose

d dimensions changed. At the most recent meeting, it was determined that the width would remain at 11.6 meters but that the length would increase by 3.7 meters. So, the pool would now cover an area of 205.85 square meters.
Which equation can be used to determine the original length of the pool, l?


205.85=2(l+15.3)

205.85=11.6(l+3.7)

205.85=3.7(l+11.6)
Mathematics
1 answer:
kobusy [5.1K]2 years ago
6 0

The equation that can be used to determine the original length of the pool is 205.85 = 11.6(l + 3.7)

Let l be the original length of the pool.

Since the length of the pool is increased by 3.7 m, the new length L = l + 3.7.

Also, the area of the pool A = 205.85 square meter and it is a rectangle with width, W = 11.6 meters,

So, A = LW

Substituting the values of the variables into the equation, we have

A = LW

205.85 = (l + 3.7)11.6

So, the equation that can be used to determine the original length of the pool is 205.85 = 11.6(l + 3.7)

Learn more:

brainly.com/question/12932084

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Answer:

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Step-by-step explanation:

9/sin(34) = 6/sinC

sinC = 0.372795269

C = 21.9, 158.1

Since 158.1 + 34 = 192.1 > 180

It will not form a triangle

So,

Only one triangle with angle 21.9° at C

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3 years ago
What is the following expression mulituply out (5x-6y)(5x-6y)
Anna007 [38]

Answer:

25x^2 - 60xy + 36y^2

Step-by-step explanation:

(5x - 6y) ( 5x - 6y)

Use foil to get the result when this is expanded.

F: (first term in each factor): 5x*5x = 25x^2

I:  Use the last term first factor multiplied by first term second factor

- 6y * 5x = - 30xy

O:Outside. Use first term first factor and last term second factor

5x * -6y = - 30xy

L: last term in both factors -6y * - 6y = 36y^2

All them together

25x^2 - 30xy - 30xy + 36y^2

and combine

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2 years ago
(a) A house costs 36% more today than when it
HACTEHA [7]

hi it me and I will be there

3 0
1 year ago
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Solve for the given variable.<br> a. 4y + 3 = 19<br><br> b. 1<br> 2n - 3 = 5
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Answer:

y=4

Step-by-step explanation:

4y+3=19

=4y=19-3

=y=16/4=4

4 0
3 years ago
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Un apostador pierde en su primer juego el 30% de su dinero, en el segundo juego pierde el 50% de lo que perdió; finalmente en el
sergiy2304 [10]

Responder:

26,62

Explicación paso a paso:

Sea x el dinero original que tenía el jugador:

si un jugador pierde en su primer juego el 30% de su dinero, la cantidad perdida será;

= 30/100 \ of \ x\\= 0.3x

Si en el segundo juego pierde el 50% de lo que perdió, entonces la cantidad perdida en el segundo juego será:

= 50/100 \ of \ 0.3x\\= 0.5 \times 0.3x\\= 0.15x

Si en el tercer juego pierde el 40% de todo lo que ha perdido, la cantidad perdida en el tercer juego será:

=\frac{40}{100} \ of \ (0.3x+0.15x) \\= 0.4(0.45x)\\= 0.2025x

Si la cantidad que le queda para seguir apostando es de 37 soles, entonces para calcular la cantidad original que tiene, sumaremos toda la cantidad perdida y la cantidad restante y equipararemos la cantidad original x como se muestra:

0,3x + 0,15x + 0,2025x + 37 = x

0,6525x + 37 = x

x-0,6525x = 37

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x = 37 / 0,3475

x = 106,48

La cantidad que tenía originalmente era de 106,48

75% de 106,48

= 75/100 * 106,48

= 0,75 * 106,48

= 79,86

Tomando la diferencia entre su monto original y su 75% será:

= 106.48-79.86\\= 26.62

3 0
3 years ago
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