Solution :
It is given that dilute hydrochloric acid is titrated with sodium carbonate solution.
of a 0.100
of hydrocholric acid is used.
Thus, 10 mL of the 0.1 molar dilute hydrochloric acid is titrated with 16.2 mL of Sodium carbonate solution.
The equation would be :
Now we know that that the
Molarity = ![$\frac{n}{v} \times 100$](https://tex.z-dn.net/?f=%24%5Cfrac%7Bn%7D%7Bv%7D%20%5Ctimes%20100%24)
For hydrochloric acid solution,
![$0.1=\frac{n}{10} \times 100$](https://tex.z-dn.net/?f=%240.1%3D%5Cfrac%7Bn%7D%7B10%7D%20%5Ctimes%20100%24)
∴ n = 0.01 moles.
Now for one mole of
, two moles of HCl acid is used.
For one mole of HCl, one-half mole of
is required.
Therefore, for 0.01 mole of HCl, we require 0.005 mole of
.
Hence, 0.01 mole of hydrochloric acid and 0.005 mole of
solution is used.
The color turns red when methyl orange indicator is used in HCl acid.
Answer:
2.34 gms left
Explanation:
3 weeks = 21 days = 7 half lives
300 * (1/2)^7 = 2.34 gms
D. a change in color of a substance