1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Natalija [7]
2 years ago
5

If 1 kg of benzene (c6h6) is oxidized with oxygen, how many kilograms of o2 are needed to convert all of the benzene to co2 and

h2o?
Chemistry
1 answer:
joja [24]2 years ago
6 0

Taking into account the reaction stoichiometry, 3,076.923 grams or 3.076 kg of O₂ are required to react when 1 kg of benzene is oxidized.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 C₆H₆ + 15 O₂ → 12 CO₂ + 6 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • C₆H₆: 2 moles
  • O₂: 15 moles
  • CO₂: 12 moles
  • H₂O: 6 moles

The molar mass of the compounds is:

  • C₆H₆: 78 g/mole
  • O₂: 32 g/mole
  • CO₂: 44 g/mole
  • H₂O: 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • C₆H₆: 2 moles ×78 g/mole= 156 grams
  • O₂: 15 moles ×32 g/mole= 480 grams
  • CO₂: 12 moles ×44 g/mole= 528 grams
  • H₂O: 6 moles ×18 g/mole= 108 grams

<h3>Mass of O₂ required</h3>

The following rule of three can be applied: If by reaction stoichiometry 156 grams of benzene react with 480 grams of O₂, 1000 grams (1 kg=1000 grams) of benzene react with how much mass O₂?

mass of O_{2} =\frac{1000 grams of benzenex480 grams ofO_{2} }{156grams of benzene}

<u><em>mass of O₂= 3,076.923 grams</em></u>

Finally, 3,076.923 grams or 3.076 kg of O₂ are required to react when 1 kg of benzene is oxidized.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

You might be interested in
Lab 27. stoichiometry and chemical reactions: which balanced chemical equation best represents the thermal decomposition of sodi
Cloud [144]
Answer:
             Sodium Bicarbonate on decomposition produces Carbon dioxide gas and Water vapors.

<span>                       2 NaHCO</span>₂<span> </span> →<span>  Na</span>₂<span>CO</span>₃<span> (s)  </span>+ <span> CO</span>₂<span> (g)  +  H</span>₂<span>O (g)
</span>
Explanation:
                   Let suppose you burn 168 g ( 2 moles ) of NaHCO₃, a gas will produced and product is left behind. On measuring the product formed it will be almost equal to 105 g. This shows that the product is Na₂CO₃ and 1 mole of it is being produced after decomposition of sodium bicarbonate.
5 0
3 years ago
The combustion of gasoline produces carbon dioxide and water. Assume gasoline to be pure octane (C8H18) and calculate the mass (
Mariulka [41]

Answer:

3.09kg

Explanation:

First, let us write a balanced equation for the reaction. This is illustrated below:

2C8H18 + 25O2 —> 16CO2 + 18H2O

Molar Mass of C8H18 = (12x8) + (18x1) = 96 + 18 = 114g/mol

Mass of C8H18 from the balanced equation = 2 x 114 = 228g

Converting 228g of C8H18 to kg, we obtained:

228/1000 = 0.228kg

Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g/mol

Mass of CO2 from the balanced equation = 16 x 44 = 704g

Converting 704g of CO2 to kg, we obtained:

704/1000 = 0.704kg

From the equation,

0.228kg of C8H18 produced 0.704kg of CO2.

Therefore, 1kg of C8H18 will produce = 0.704/0.228 = 3.09kg of CO2

6 0
3 years ago
What did Kwang Jeon discover when researching amoeba infected by bacteria?
defon
<span>Kwang Jeon observed that Amoeba had been attacked by a bacterial infection, and lots of the Amoeba had died. However, some survived and continued to reproduce. After investigating the remaining Amoeba and their offspring, he noticed they were very healthy. He thought maybe they were able to fight off the bacteria, but instead, he found they were still infected with the bacteria but were not dying. The bacteria were no longer making the Amoeba sick. Then, he killed off the bacteria using antibiotics and was surprised to see that the Amoeba also died. It seemed the Amoeba and bacteria had formed a relationship in which they both needed each other to survive. After researching, Jeon found that the bacteria made a protein that the Amoeba needed to survive. </span>
6 0
3 years ago
5.00 L of air at 750 mmHg pressure was compressed into a 3.00 L steel cylinder. What is the final pressure? (round to significan
kozerog [31]

Answer:

P2 = 1250mmHg

Explanation:

V1 = 5.0L

P1 = 750mmHg

V2 = 3.0L

P2 = ?

According to Boyle's law, the volume of a fixed mass of gas is inversely proportional to its pressure provided that temperature remains constant.

P = k/V k = P*V

P1*V1 = P2*V2 = P3*V3 =........=Pn*Vn

P1 *V1 = P2 * V2

Solve for P2

P2 = (P1 * V1) / V2

P2 = (750 * 5.0) / 3.0

P2 = 3750 / 3

P2 = 1250mmHg

The final pressure of the gas is 1250mmHg

5 0
3 years ago
What is the formula mass of ethyl alcohol, C2H5OH
Fofino [41]
<span>46.06844 g/mol
yup
yup
yup</span>
4 0
3 years ago
Other questions:
  • If the ph of a solution is decreased from ph 8 to ph 6 it means that the
    9·2 answers
  • BRAINIEST IF ANSWERED CORRECTLY IN THE NEXT 5M
    14·2 answers
  • What is the slope of a line that is perpendicular to the line shown?
    14·2 answers
  • What alcohol is formed when the alkene is treated with h2o in the presence of h2so4? qs14?
    9·1 answer
  • What is the molar mass of magnesium
    6·1 answer
  • What is an intensive property? *
    6·1 answer
  • Phosphorus-33 has a half-life of 25 days. What fraction of the original sample would remain after 300 days?
    10·1 answer
  • Please help me with this <br> Beer Lambert Law Explanation
    6·1 answer
  • What are the evidences for suspecting the presence of waves?
    9·1 answer
  • How can the actions of people affect runoff and absorption in a positive way? How do they affect them in a negative way?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!