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finlep [7]
2 years ago
9

Which is the most likely meaning of the word anachronous? (1 point)

Mathematics
1 answer:
ad-work [718]2 years ago
6 0

Answer:

Not in the right time

Step-by-step explanation:

ana is the root of before and chronous=krounus, being the Greek word for time.

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Matt walked 1 mile in 15 minutes. At this rate, how many miles would he walk in 2 hours?
Aleonysh [2.5K]
I think the answer is 8
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3 years ago
Estimate the value of 1573 + 1211<br> - 697.
Mumz [18]

Answer:

2100

Step-by-step explanation:

6 0
3 years ago
find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM​
Snezhnost [94]

\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}

  • Given - <u>A </u><u>trapezium</u><u> </u><u>ABCD </u><u>with </u><u>non </u><u>parallel </u><u>sides </u><u>of </u><u>measure </u><u>1</u><u>5</u><u> </u><u>cm </u><u>each </u><u>!</u><u> </u><u>along </u><u>,</u><u> </u><u>the </u><u>parallel </u><u>sides </u><u>are </u><u>of </u><u>measure </u><u>1</u><u>3</u><u> </u><u>cm </u><u>and </u><u>2</u><u>5</u><u> </u><u>cm</u>

  • To find - <u>Area </u><u>of </u><u>trapezium</u>

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

<u>Construction</u><u> </u><u>-</u>

draw \: CE \: \parallel \: AD \:  \\ and \: CD \: \perp \: AE

Now , we can clearly see that AECD is a parallelogram !

\therefore AE = CD = 13 cm

Now ,

AB = AE + BE \\\implies \: BE =AB -  AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm

Now , In ∆ BCE ,

semi \: perimeter \: (s) =  \frac{15 + 15 + 12}{2}  \\  \\ \implies \: s =  \frac{42}{2}  = 21 \: cm

Now , by Heron's formula

area \: of \: \triangle \: BCE =  \sqrt{s(s - a)(s - b)(s - c)}  \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)}  \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21}  \: cm {}^{2}

Also ,

area \: of \: \triangle \:  =  \frac{1}{2}  \times base \times height \\  \\\implies 18 \sqrt{21} =  \: \frac{1}{\cancel2}  \times \cancel12  \times height \\  \\ \implies \: 18 \sqrt{21}  = 6 \times height \\  \\ \implies \: height =  \frac{\cancel{18} \sqrt{21} }{ \cancel 6}  \\  \\ \implies \: height = 3 \sqrt{21}  \: cm {}^{2}

<u>Since </u><u>we've </u><u>obtained </u><u>the </u><u>height </u><u>now </u><u>,</u><u> </u><u>we </u><u>can </u><u>easily </u><u>find </u><u>out </u><u>the </u><u>area </u><u>of </u><u>trapezium </u><u>!</u>

Area \: of \: trapezium =  \frac{1}{2}  \times(sum \: of \:parallel \: sides) \times height \\  \\ \implies \:  \frac{1}{2}  \times (25 + 13) \times 3 \sqrt{21}  \\  \\ \implies \:  \frac{1}{\cancel2}  \times \cancel{38 }\times 3 \sqrt{21}  \\  \\ \implies \: 19 \times 3 \sqrt{21}  \: cm {}^{2}  \\  \\ \implies \: 57 \sqrt{21}  \: cm {}^{2}

hope helpful :D

6 0
2 years ago
Triangle JKL is dilated from the origin at a scale factor of 10 to create triangle J′K′L′.Select the option that completes the s
Aneli [31]

Given: Triangle JKL is dilated from the origin at a scale factor of 10 to create triangle J′K′L′.

Required: Correct option that complete the statement.

Explanation:

Now, triangle is dilated from the origin at a scale factor of 10.

So, the sides will become larger, but angles will remain the same.

Hence, the triangles will be similar as sides will be in proption (SSS rule).

So, The triangles are similar because their corresponding sides are proptional and their corresponding angles are congurent.

Final Answer: Second group is correct answer.

5 0
1 year ago
What’s 4x + 7y + 4 + 5x + y
fomenos

Hello!

Okay, so first we need to add like terms... so first, add the terms with the same variables. That gives us:

9x + 7y + 4 + y

Now add 7y and y

That gives us:

9x + 8y + 4

This can't be added anymore... this is as far as we can go because they are no longer like terms.

6 0
3 years ago
Read 2 more answers
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