Answer:
2100
Step-by-step explanation:

- Given - <u>A </u><u>trapezium</u><u> </u><u>ABCD </u><u>with </u><u>non </u><u>parallel </u><u>sides </u><u>of </u><u>measure </u><u>1</u><u>5</u><u> </u><u>cm </u><u>each </u><u>!</u><u> </u><u>along </u><u>,</u><u> </u><u>the </u><u>parallel </u><u>sides </u><u>are </u><u>of </u><u>measure </u><u>1</u><u>3</u><u> </u><u>cm </u><u>and </u><u>2</u><u>5</u><u> </u><u>cm</u>
- To find - <u>Area </u><u>of </u><u>trapezium</u>
Refer the figure attached ~
In the given figure ,
AB = 25 cm
BC = AD = 15 cm
CD = 13 cm
<u>Construction</u><u> </u><u>-</u>

Now , we can clearly see that AECD is a parallelogram !
AE = CD = 13 cm
Now ,

Now , In ∆ BCE ,

Now , by Heron's formula

Also ,

<u>Since </u><u>we've </u><u>obtained </u><u>the </u><u>height </u><u>now </u><u>,</u><u> </u><u>we </u><u>can </u><u>easily </u><u>find </u><u>out </u><u>the </u><u>area </u><u>of </u><u>trapezium </u><u>!</u>

hope helpful :D
Given: Triangle JKL is dilated from the origin at a scale factor of 10 to create triangle J′K′L′.
Required: Correct option that complete the statement.
Explanation:
Now, triangle is dilated from the origin at a scale factor of 10.
So, the sides will become larger, but angles will remain the same.
Hence, the triangles will be similar as sides will be in proption (SSS rule).
So, The triangles are similar because their corresponding sides are proptional and their corresponding angles are congurent.
Final Answer: Second group is correct answer.
Hello!
Okay, so first we need to add like terms... so first, add the terms with the same variables. That gives us:
9x + 7y + 4 + y
Now add 7y and y
That gives us:
9x + 8y + 4
This can't be added anymore... this is as far as we can go because they are no longer like terms.