Answer: what is the problem
Step-by-step explanation:
Answer:
4' - 9.64
Step-by-step explanation:
Total rise = 2' - 7"
Total run = 3' - 9"
Converting to inches :
1' = 12" ; 1 feet = 12 inches
2' = 2 * 12 = 24"
3' = 3 * 12 = 36"
Total rise = 24" + 7" = 31"
Total run = 36" + 9" = 45"
Length of stringer = hypotenus
Hypotenus = √(total rise² + total run²)
Hypotenus = √(31² + 45²)
Hypotenus = 54.644304"
= 4' - 9.64"
First one single solution second no solution 3rd one single forth one infinity and last 2 are single and infinity
Given that the diameter: d= 0.0625 inch.
So, radius of the wire : r =
= 0.03125 inch
Now the formula to find the cross-sectional area of wire ( circle) is:
A = πr²
= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125
=3.14 * 0.000976563
= 0.003066406
= 0.00307 (Rounded to 5 decimal places).
Hence, cross-sectional area of a wire is 0.00307 square inches.
Hope this helps you!