Let's go over the given information. We have the volume, temperature and pressure. From the ideal gas equation, that's 4 out of 5 knowns. So, we actually don't need Pvap of water anymore. Assuming ideal gas, the solution is as follows:
PV=nRT
Solving for n,
n = PV/RT = (753 torr)(1 atm/760 torr)(195 mL)(1 L/1000 mL)/(0.0821 L·atm/mol·K)(25+273 K)
n = 7.897×10⁻³ mol H₂
The molar mass of H₂ is 2 g/mol.
Mass of H₂ = 7.897×10⁻³ mol * 2 g/mol = <em>0.016 g H₂</em>
Answer:
A - Chemical potential energy being converted to heat energy
Explanation:
<span>the answer is
C. The bar for very low concentration is twice the height of the bar for medium concentration.
proof
</span>
<span>
</span>
<span>Medium--------------------15
</span>Very Low-------------------30 = 2<span /> x 15 (<span>Medium)
</span>
Beryllium Oxide has a molecular formula Be-O
% covalent character in Be-O = 100 - % ionic character in Be-O
Now,
% ionic character = {1 - exp[(-0.25)(E(Be)-E(O))²]}*100
where,
E(Be) and E(O) are the electronegativity values of Be and O
Based on the Paulings scale:-
E(Be) = 1.57
E(O) = 3.44
% ionic = {1 - exp[(-0.25)(1.57-3.44)²]}*100 = 58.28%
Therefore, % covalent = 100 -58.28 = 41.72%
Ans: b) 41 percent
