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Helga [31]
3 years ago
5

Define physical change and give an example

Chemistry
2 answers:
Musya8 [376]3 years ago
6 0
Physical isn't so chemical

frozen [14]3 years ago
3 0
Physical changes are the physical properties associated with a specific matter. 

Examples include viscosity, malleability, colour, odor, hardness, etc. 
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Which one of these elements is an alkaline earth metal
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The answer to this problem is Beryllium is an alkaline earth metal.
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A compound composed of nickel and fluorine contains 9.11 g ni and 5.89 g f. what is the empirical formula of this compound
aalyn [17]
Empirical formula is the simplest formula showing the simplest ratio of atoms in a compound. Calculated as shown;
 we start by calculating the number of moles of each atom;
moles of nickel = 9.11 g ÷ 58.7 g = 0.155 moles 
moles of fluorine = 5.89 g ÷ 19 g = 0.31 moles
Then we get the ratio of the moles of nickel to that of flourine
 That is 0.155 : 0.31  (dividing by the smallest)
            0.155/0.155 : 0.31/0.155
we get 1:2  ( the simplest ratio)
Therefore the empirical formula is nif2 
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3 years ago
Which of the following measurements are recorded to three significant figures? Select all that apply.
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C and D have three significant figures.
4 0
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What elects have properties like iron
Elis [28]

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Cobalt and nickel are trace elements with properties similar to iron.

3 0
3 years ago
To test the effectiveness of a gunpowder mixture, 1 gram was exploded under controlled STP conditions, and the reaction chamber
Phoenix [80]

Answer:

The volume of the gas at given temperature is 1300 cm^3

Explanation:

P_1 = initial pressure of gas = 1 atm

T_1 = initial temperature of gas = 0^oC=273.15 K

V_1 = initial volume of gas = 310 cm^3 = 310 mL = 0.310 L

(1 cm^3= 1mL , 1 mL = 0.001 L)

P_1V_1=nRT_1..[1]

P_2 = final pressure of gas = 2.1 atm

T_2 = final temperature of gas = 2,200^oC=273+2200 K=2473.15 K

V_2 = final volume of gas = ?

P_2V_2=nRT_2..[2]

By dividing [1] and [2] we get combined gas equation :,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

V_2=\frac{P_1V_1\times T_2}{T_1\times P_2}

Now put all the given values in the above equation, we get:

V_2=\frac{1 atm\times 0.310 L\times 2473.15 K}{273.15 K\times 2.1 atm}

V_2=1.3 L=1300 mL= 1300 cm^3

The volume of the gas at given temperature is 1300 cm^3

3 0
4 years ago
Read 2 more answers
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