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3 years ago

Which relation is also a function?

2 answers:

8 0

A function will not have any repeating x values...they all have to be different. They can have repeating y values, just not the x ones.

so ur sets of numbers are all set up like (x,y). Now look through ur answer choices and which one has all different x values ? That will be ur function.

ur answer is : { (-4,-3), (0,-3), (1,-3), (4,-3)}.....and as u can see, all the x values {-4,0,1,4} are different.

stich3 [128]3 years ago

7 0

Answer:

A function will not have any repeating x values...they all have to be different. They can have repeating y values, just not the x ones.

so ur sets of numbers are all set up like (x,y). Now look through ur answer choices and which one has all different x values ? That will be ur function.

ur answer is : { (-4,-3), (0,-3), (1,-3), (4,-3)}.....and as u can see, all the x values {-4,0,1,4} are different.

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Brian tied a 136-foot rope around the perimeter of his rectangular house. He knows that the length of the house is 10 feet less

STALIN [3.7K]

Answer:

length 42 cm and width 26 cm

Step-by-step explanation:

Given

Since Brian tied 136 foot rope around the perimeter , hence perimeter of house is 136 foot.

Given that shape of house is rectangular.

formula to calculate perimeter of rectangle can be used which is 2*(L+B)

where L is length of rectangle and B width of rectangle

Let the L and B be length of rectangular side of house

According to question

length of house is 10 feet less than twice the width of house

mathematically it can be represented as

L = 2*B - 10 --->eq. 1

Perimeter of house = 136 feet

using formula of Perimeter of rectangle

136 = 2*(L+B)

substituting the value of length in terms of width from eq. 1 in formula of perimeter

=> 136/2 = 2*B - 10 + B (2*B+ B = 3B)

=> 68 = 3*B - 10

=> 78 = 3*B

B = 78/3 = 26

Therefore B which is width = 26 CM

length = 2*B - 10= 26*2 - 10 = 52-10=42

length of house = 42 cm

Hence dimension of Brian's house is length 42 cm and width 26 cm

5 0

3 years ago

A drug is eliminated from the body through urine. Suppose that for a dose of 10 milligrams, the amount A(t) remaining in the bod

adell [148]

Answer: a - 4.512 hours

b - 1.94 hours

Step-by-step explanation:

Given,

a) A(t) = 10 (0.7)^t

To determine when 2mg is left in the body

We would have,

A(t) = 2, therefore

2 = 10(0.7)^t

0.7^t =2÷10

0.7^t = 0.2

Take the log of both sides,

Log (0.7)^t = log 0.2

t log 0.7 = log 0.2

t = log 0.2/ 0.7

t = 4.512 hours

Thus it will take 4.512 hours for 2mg to be left in the body.

b) Half life

Let A(t) = 1/2 A(0)

Thus,

1/2 A(0) = A(0)0.7^t

Divide both sides by A(0)

1/2 = 0.7^t

0.7^t = 0.5

Take log of both sides

Log 0.7^t = log 0.5

t log 0.7 = log 0.5

t = log 0.5/log 0.7

t = 1.94 hours

Therefore, the half life of the drug is 1.94 hours

6 0

3 years ago

Mary places a miniature car onto a track with launchers. The speed of the car is recorded every foot. Some of the data is shown

Arada [10]

Answer:

5 or less

Step-by-step explanation:

The speed increased linearly with distance, but is not decreasing linearly with distance. This suggests the track has an unknown shape, so prediction of car behavior is a guess, at best.

If the car continues to decrease its speed at 3 units per unit distance, then the final 3 units of speed will decrease to 0 in one additional unit of distance. That is, the car will stop at a distance of 5 units.

___

Since the car has be decreasing its speed at an increasing rate with respect to distance, very possibly the car will stop before it reaches distance unit 5.

Since we don't know the track shape, it seems possible the car may not stop until some large unknown number of distance units, say 10 or 1000.