1. Solve the bracket 4×x and 4 × -7
4x-28=2x-6
2. Get the x on one side and the numbers on the other so: first +28
4x=2x+22 now -2x
so 2x=22 and now you only need to divide into 2
x=11

3 0

3 years ago

By use of technology, we investigated Mary’s investment and created the model, M(x) = 3.03(1.28)2x, in thousands of dollars. Wha

aleksandr82 [10.1K]

The initial investment was 3.03 because this is the value that does not change and comes before the value with the exponent "2x" is mentioned.

6 0

3 years ago

Read 2 more answers

A pool in the shape of s rectangle has a perimeter 80 feet. The pool is 8 feet less wide than it is long

kykrilka [37]

So, 80 - 8. equals 72 / 2 = 36... then add 36 + 8 to one and you have 44...
44 for length and 36 for width

3 0

3 years ago

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An ice cube is melting, and the lengths of its sides are decreasing at a rate of 0.8 millimeters per minute At what rate is the

julia-pushkina [17]

Answer:

The rate of decrease is: $43.2mm^3/min$

Step-by-step explanation:

Given

$l = 18mm$

$\frac{dl}{dt} = -0.8mm/min$ ---- We used minus because the rate is decreasing

Required

Rate of decrease when: $l = 18mm$

The volume of the cube is:

$V = l^3$

Differentiate

$\frac{dV}{dl} = 3l^2$

Make dV the subject

$dV = 3l^2 \cdot dl$

Divide both sides by dt

$\frac{dV}{dt} = 3l^2 \cdot \frac{dl}{dt}$

Given that: $l = 18mm$ and $\frac{dl}{dt} = -0.8mm/min$

$\frac{dV}{dt} = 3 * (18mm)^2 * (-0.8mm/min)$

$\frac{dV}{dt} = 3 * 18 *-0.8mm^3/min$

$\frac{dV}{dt} = -43.2mm^3/min$

<em>Hence, the rate of decrease is: 43.2mm^3/min</em>

8 0

3 years ago