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Fudgin [204]
3 years ago
12

Write a function named parts that will take in as parameters the dimensions of the box (length, width, and height) and the radiu

s of the hole, and returns the volume of material remaining. Assume the hole has been drilled along the height direction. Note: first write the function assuming the hole has radius less than min(length/2, width/2). For full credit, you will need to account for larger radii (bigger than half the length or width of the box).
Computers and Technology
1 answer:
iren [92.7K]3 years ago
3 0

The function in Python where comments are used to explain each line is as follows:

#This defines the parts() function

def parts(length, width, height, radius):

   #This calculates the volume of the box

   VBox = length * width * height

   #This calculates the volume of the hole

   VHole = 3.142 * radius ** 2 * height

   #This calculates the remaining volume

   Volume =  VBox - VHole

   #This returns the volume of the remaining material

   return Volume

The above program is a sequential program, and it does not require loops, iterations and conditions.

Read more about similar programs at:

brainly.com/question/13971394

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Answer:

Thanks for it

Explanation:

Brainlists please

3 0
3 years ago
Read 2 more answers
Your laptop LCD panel is blank when you boot up. You can hear the laptop turn on, and the keyboard backlight is on. You have che
kati45 [8]

Answer:

Plug the laptop to a desktop monitor.

Explanation:

Assuming that the damaged component its the LCD screen and nothing else, the laptop would still be able to work correctly when connected to a desktop monitor, with an HDMI, or VGA cable. Thus you will find out that you only need to replace the screen and your graphic processor and other components are functional. Also if you need to work with your laptop and can't wait for the replacement, you can do still do it. Your keyboard and mouse are still functional, so you will see and work on your desktop monitor.

8 0
3 years ago
Acceleration is the rate at which an object changes its velocity. It is typically represented by symbol a and measured in m/s2 (
Natalija [7]

Answer:

<u>Pseudocode:</u>

INPUT velocity

INPUT time

SET velocity = 0.44704 * velocity

SET acceleration = velocity / time

SET acceleration = round(acceleration, 1)

PRINT acceleration

<u>Code:</u>

velocity = float(input("Enter a velocity in miles per hour: "))

time = float(input("Enter a time in seconds: "))

velocity = 0.44704 * velocity

acceleration = velocity / time

acceleration = round(acceleration, 1)

print("The acceleration is {:.2f}".format(acceleration))

Explanation:

*The code is in Python.

Ask the user to enter the velocity and time

Convert the miles per hour to meters per second

Calculate the acceleration using the formula

Round the acceleration to one decimal using round() method

Print the acceleration with two decimal digits

7 0
3 years ago
When filtering for unique values only, ______ will be hidden from view
alukav5142 [94]
Greetings. 


l think it is going to be history. Hope it helped 

If not plz let me know
4 0
4 years ago
Program 7 - Circle You write ALL the code, then run it - Produce the correct output. Turn in code and screen print of successful
fgiga [73]

Answer:

Here is the Circle class:

public class Circle {   // class definition

private int radius;    // private data member of type int of class Circle named radius that stores the value of radius

public Circle(int r) {   // parameterized constructor of class Circle that takes radius as argument

 radius = r;  }    // sets value of radius as r

public int getRadius() {   // accessor method to get the value of radius

 return radius;  }   // returns the current value of radius

public int Diameter() {   // method to compute diameter of a circle

 return radius * 2;  }   // multiply radius value by 2 to compute diameter of Circle

 

public double Area() {   // method to compute area of a circle

 return Math.PI  * Math.pow(radius, 2);   }   //the formula of area is

π x radius² where value of π is get using Math.PI

 

 public double Circumference() {   // // method to compute circumference of a circle

 return 2* Math.PI * radius;   }   }  //the formula of circumference is

2 x π x radius where value of π is get using Math.PI

Explanation:

Here is the Main class:

import java.util.Scanner;  //to accept input from user

public class Main {  //definition of Main class

public static void main(String[] args) {  //start of main method

   

    Scanner scanner = new Scanner (System.in);  //creates Scanner object to take input from user

    System.out.println("Enter radius: ");  //prompts user to enter radius

    int r = scanner.nextInt();  //reads the value of radius from user

 Circle c = new Circle(r);  // calls Constructor of Circle passing r as argument to it using the object c of class Circle

 

    if(c.getRadius()<=0){  //calls getRadius method to get current value of radius using objec and checks if this value (input value of r ) is less than or equal to 0

        System.out.println("Error!");   }  //when above if condition evaluates to true then print this Error! message

    else {  //if the value of radius is greater than 0

System.out.println("the radius of this Circle is: " +c.getRadius());  //calls getRadius method to return current value of r (input value by user)

System.out.println("the diameter of this Circle  is: " + c.Diameter());  //calls Diameter method to compute the diameter of Circle and display the result on output screen

System.out.printf("the circumference of this Circle  is: %.2f", c.Circumference());  //calls Circumference method to compute the Circumference of Circle and display the result on output screen

System.out.println();  //prints a line

System.out.printf("the Area of this Circle  is: %.2f", c.Area()); } }  }

//calls Area method to compute the Area of Circle and display the result on output screen

The program and its output is attached.

7 0
3 years ago
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