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2 years ago

Of all the numbers whose difference is 10, find the two that have the minimum product

Mathematics

1 answer:

Nostrana [21]2 years ago

7 0

Answer: -9

Step-by-step explanation: You might think that the smallest two numbers are 11 and 1 but there are negative numbers. 1 - (-9) is equal to 10. 1 x (-9) is -9.

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X(x^3+4x^2-65x+132)=0

Nonamiya [84]

Answer:

0,3,4,-11

Step-by-step explanation:

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3 years ago

8/9 - Evaluating Algebraic Expressions

Alecsey [184]

9514 1404 393

Answer:

(a) 20

Step-by-step explanation:

Put the numbers in place of the corresponding letters and do the arithmetic.

4(5) -((-3) +5) +2 = 20 -2 +2 = 20

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3 years ago

Two vertical poles of heights 60 ft and 80 ft stand on level ground, with their bases 100 ft apart. A cable that is stretched fr

Andreyy89

Answer:

Step-by-step explanation:

Given

height of two Poles are 60 and 80 ft

Distance between them is 100 ft

Let x be the distance of Pole of ht 80 ft from Point of stretch

thus length of rope is given by

$L=L_1+L_2$

$L_1=\sqrt{80^2+x^2}$

$L_2=\sqrt{60^2+(100-x)^2}$

$L=\sqrt{80^2+x^2}+\sqrt{60^2+(100-x)^2}$

differentiate w.r.t x we get

$\frac{\mathrm{d} L}{\mathrm{d} x}=\frac{2x}{2\sqrt{80^2+x^2}}-\frac{2\left ( 100-x\right )}{\sqrt{60^2+\left ( 100-2x\right )^2}}$

Put $\frac{\mathrm{d} L}{\mathrm{d} x}=0$ to get minimum value

$\frac{2x}{2\sqrt{80^2+x^2}}=\frac{2\left ( 100-x\right )}{\sqrt{60^2+\left ( 100-2x\right )^2}}$

squaring

$x^2\left ( (100-x)^2+60^2\right )=(100-x)^2(80^2+x^2)$

Rearranging

$28x^2-1800x+640000=0$

$x=\frac{400}{7}$

thus $L_1=98.312 ft$

$L_2=73.73 ft$

$L=172.04 ft$

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3 years ago

The area of a square is (9a2 − 24a + 16) square units. determine the length of each side of the square by factoring the area exp

Anton [14]

The will be 3x+4 I hope this help you

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3 years ago

Jessie's bus ride to school is 5 minutes more then 2/3 the time roberts bus ride. if jessie's time riding the bus is y and rober

Rainbow [258]

X=2/3y because you want to know what roberts time is

7 0

4 years ago