How do do a word problem whit five hundred and four

1 answer:

7 0

Ronald has $504 to spend at the mall. He buys a shirt that cost $20 and a pair of shoes for $35. His friend loans him $55. How much does Ronald have now?

Ronald still has $504.

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The force of an object (f) is equal to its mass (m) times its acceleration (a). Thus, the formula for calculating force is f = m

irina [24]

Acceleration = force ÷ mass: a = f/m

3 0

3 years ago

Read 2 more answers

Prove that:

photoshop1234 [79]

(a) 5^31-5^29 = 5^29(5^2-1)

= 5^29(24)
= 5^29(6)(4)
=5^26(6)*[(5)(5)(4)]
=5^26(6)*100
(b) 25^9+5^17 = 5^18+5^17
=5^17(5+1)
=5^17(6)
=5^16[(5)(6)]
=5^16*30
(c) 27^10â€“9^14 = 3^30-3^28
=3^28(3^2 -1)
=3^28(8)
=3^27[(3)(8)]
=3^27*24

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3 years ago

Need steps on how to factor 3x^4 + x^3 + 6x^2 + 2x

ella [17]

Answer:

3x times 3x times 3x times 3x + x^3 + 3x times 2x times 3x times 2x + 2x

x^3 + 2x^3 + 3x^6

Step-by-step explanation:

3x^4 + x^3 + 6x^2 + 2x

3x times 3x times 3x times 3x + x^3 + 6x times 6x + 2x

3x times 3x times 3x times 3x + x^3 + 3x times 2x times 3x times 2x + 2x

x^3 + 2x^3 + 3x^6

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3 years ago

Clark left for school at 7:43 a.m. he got to school 30 minutes late what time did Clark get to school

lilavasa [31]

If clark left at 7:43, and 30 minutes later he arrived he would get to school around 8:13, 7:43 + 30 = 8:13

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3 years ago

An isosceles trapezoid ABCD with height 2 units has all its vertices on the parabola y=a(x+1)(x−5). What is the value of a, if p

horrorfan [7]

Answer:

a = -0.3575

Step-by-step explanation:

The points A and D lie on the x-axis, this means that they are the x-intercepts of the parabola, and therefore we can find their location.

The points A and B are located where

$y=a(x+1)(x-5)=0$

This gives

$x=-1$

$y=5$

Now given the coordinates of A, we are in position to find the coordinates of the point B. Point B must have y coordinate of y=2 (because the base of the trapezoid is at y=0), and the x coordinate of B, looking at the figure, must be x coordinate of A plus horizontal distance between A and B, i.e

$B_x=A_x+\frac{2}{tan(60)} =-1+\frac{2\sqrt{3} }{3}$