An arithmetic sequence k starts 4, 13, . . . . Explain how you would calculate the value of the 5,000th term
1 answer:
Using the concept of arithmetic sequence, the 5000th term can be obtained using the relation 4 + (5000 - 1)9
For an arithmetic sequence, the nth term is calculated using the relation :
- <em>d</em><em> </em><em>=</em><em> </em><em>common</em><em> </em><em>difference</em><em> </em>
- <em>n</em><em> </em><em>=</em><em> </em><em>nth</em><em> </em><em>term</em><em> </em>
- <em>a</em><em> </em><em>=</em><em> </em><em>first</em><em> </em><em>term</em><em> </em>
Here,
First term, a = 4
Common difference = 2nd term - 1st term = 13 - 4 = 9
nth term = 5000th term
<u>The</u><u> </u><u>expression would</u><u> </u><u>be</u><u> </u><u>:</u>
The required expression would be : T(5000) = 4 + (5000 - 1)9
Learn more : brainly.com/question/25741301
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