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Katarina [22]
2 years ago
11

The main structural distinction between the left atrium and the right atrium is that the left atrium has the _____, and the righ

t atrium does not.
a. auricle
b. pectinate muscles
c. cardiac muscles
d. chordae tendinae
Biology
1 answer:
Fiesta28 [93]2 years ago
3 0

Given our understanding of cardiac anatomy, we can confirm that the main structural distinction is that the right atrium has the pectinate muscles, while the left one does not.

Firstly, we must address that there is a wording issue with the question. In reality, it is the right atrium that contains the pectinate muscles. The remaining options either correspond to both atrium, or neither.

The auricle is another word for ear. This is a cavity present on both the right and left atrium which allows them to extend their blood carrying capacity in situations of need. This option cannot be correct for the question since both atria possess one.

As for options b and c, cardiac muscle is present in the entirety of the heart. Cardiac muscle is the muscular cells that make up every wall and cavity of the heart and allow it to complete its unique function. Chordae tendinae, are fibers present in the ventriculus that attach the walls to the tricuspid valve, these are not present in either of the atria.

Therefore, we can confirm that though the wording is off, the intended correct answer is pectinate muscles, given that the right atrium is characterized by their presence, whilst the left atrium contains few, if any, of these muscles.

To learn more visit:

brainly.com/question/7287883?referrer=searchResults

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What is the main term used to locate COPD in the alphabetic index
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What results would you expect from a biuret test of steak solution?
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A positive result.

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A population of 100 tigers has 30 with horizontal stripes. Using pedigrees, you ascertain that horizontal striping is caused by
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Assuming that this population is in Hardy-Weinberg equilibrium, we can sayt that  <em>the</em><em> probability</em><em> that, given enough time, all tigers in the population will have horizontal stripes is</em><em> 30% = 0.3.</em>

--------------------------

<u>Available data:</u>

  • Population size, N = 100 tigers
  • Number of Tigers with horizontal stripes = 30
  • Horizontal stripes is caused by an autosomal recessive mutation.

We need to know the probability that all tigers in the population will have horizontal stripes, which is the recessive phenotype.

We assume that the population is in Hardy-Weinberg equilibrium, so there should be no evolution.

Since the population is in H-W equilibrium, the allelic, genotypic and phenotypic frequencies will remain the same generation after generation.

Now, we will calculate the allelic and genotypic frequencies of horizontal striped individuals in the population.

There are 100 individuals, and only 30 have horizontal stripes.

So, the phenotypic frequency, F(HS) is 30/100 = 0.3 = 30%

Since this is a recessive phenotype, this value equals the genotypic frequency, F(hh) = 30%

Finally, we can get the allelic frequency by taking the square root of this value.

F(hh) = q² = 0.3

f(h) = q = √0.3 = 0.55 = 55%

According to these calcs, the probability for the fixation of the recessive allele is 55%, and the probability that all individuals express the recessive horizontal stripes phenotype is 30%.

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