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3 years ago

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How do the expressions 2q2−3p and 2(p+q)/q compare when p = 8 and q = 4?Drag a symbol into the box to correctly complete the sta

tement.2q2−3p Response area 2(p+q)/q when p = 8 and q = 4.=<>

2 answers:

ruslelena [56]3 years ago

7 0

Answer:

The answer is ">"

Step-by-step explanation:

I took the quiz epicly

rewona [7]3 years ago

3 0

Answer:

its > ‍♀️

Step-by-step explanation:

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Create a system of linear equations with one solution. In your final answer, include the system of equations and the graphs of t

GrogVix [38]

Answer:

<u>System of equations</u>

$x + y = 5$

$y - 2x = -4$

$(x,y) = (3,2)$ --- solution

See attachment for graph

Step-by-step explanation:

Solving (a): Linear equations with 1 solution

The only condition to this is that, the system must have 1 solution.

Other than that, there is no other condition.

A linear equation is represented as:

$ax + by= c$

For the equation to have 1 solution;

$a_1 * b_2 \ne a_2 * b_1$

And example of such equation is:

$x + y = 5$

$y - 2x = -4$

Solving (b): The graph

See attachment for graph

The solution is the point of intersection of both lines of the graph. So, we have:

$(x,y) = (3,2)$

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3 years ago

Find the equation of the problem

pogonyaev

$6\sin^2\theta-\sin\theta=1\ \ \ -1\\\\6\sin^2\theta-\sin\theta-1=0\\\\6\sin\theta-3\sin\theta+2\sin\theta-1=0\\\\3\sin\theta(2\sin\theta-1)+1(2\sin\theta-1)=0\\\\(2\sin\theta-1)(3\sin\theta+1)=0\iff2\sin\theta-1=0\ \vee\ 3\sin\theta+1=0\\\\2\sin\theta=1\ \ |:2\ \ \vee\ \ 3\sin\theta=-1\ \ |:3\\\\\sin\theta=\dfrac{1}{2}\ \vee\ \sin\theta=-\dfrac{1}{3}\\\\$
$\theta=30^o\ \vee\ \theta=150^o\ \vee\ \theta=360^o-\sin^{-1}\left(\dfrac{1}{3}\right)\ \vee\ \theta=180^o+\sin^{-1}\left(\dfrac{1}{3}\right)$

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Marysya12 [62]

Answer:

(1, -10) hope this helps

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C

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