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3 years ago

200 beads are 48$ if she needs 25 more beads hoe much will she pay if she is charged the same rate

Mathematics

2 answers:

OLEGan [10]3 years ago

8 0

All together it will be $54 but just 25 beads is $6.

frez [133]3 years ago

4 0

The answer is 6 you have to divide 48 divided by 200 find the answer then multiply that by 25

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34kurt

Cos theta would be (adjacent side) / (hypotenuse), or 8/29.

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1.291 radians or 73.987 degrees.

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6 0

3 years ago

I cut a long piece of wood into 50cm pieces. I manage to cut

ehidna [41]

Answer:

$WoodLength = 50w + 20$

Step-by-step explanation:

Given

Length of Pieces = 50cm

Number of Pieces = w

Left over = 20cm

Required

Determine the length of the wood

Start by multiplying the number of pieces by the length of each pieces

$Result = Length * Number$

$Result = 50 * w$

$Result = 50 w$

Lastly, add the leftover to get the actual length of the wood

$Wood Length = Result + Leftover$

Substitute 50w for Result and 20 for Leftover

$WoodLength = 50w + 20$

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5 0

3 years ago

The parents club wants to sell buttons to raise money for the local community center sports program. The buttons cost 60 cents e

astraxan [27]

Their profit made will be 4,420

This is because 0.60 x 1300 is 780

And the amount they will make by selling is $5200, because 1300 x 4

So we will do 5200 - 780, and that is the profit made- $4,420

3 0

4 years ago

Read 2 more answers

Kevin is 3 times as old as Daniel. 4 years ago, Kevin was 5 times as old as Daniel. How old is Daniel now

matrenka [14]

7 0

3 years ago

NutritionCalc Plus uses the equations from the National Academy of Medicine to calculate the Estimated Energy Requirement (EER)

olga nikolaevna [1]

Answer:

The correct option is (A).

Step-by-step explanation:

The equation for the Estimated Energy Requirement (EER) of 19 or more years older men is:

$EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)$

Here,

AGE = age counted in years

PA = appropriate physical activity factor

WT = weight in kilograms

HT = height in meters

The physical activity factor for men and women is:

Activity Level PA (men) PA (Women)

Sedentary 1.00 1.00

Low 1.11 1.12

Active 1.25 1.27

Very Active 1.48 1.45

Given:

AGE = 22 year-old male college student

PA = low = 1.11

WT = 180 pounds = 81.6466 kg

HT = 5'10" = 1.778 m

Compute the value of EER as follows:

$EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)$

$= 662 - (9.53 \times 22) + 1.11 \times (15.91 \times 81.6466 + 539 \times 1.778)\\\\=662-209.66+1.11\times (1298.997406+958.342)\\\\=452.34+2505.64674066\\\\=2957.98674066\\\\\approx 2962$

Thus, the EER for a 22-year-old male college student is approximately 2962 kcal.

The correct option is (A).

6 0

3 years ago