F(x) = -x² + 25
g(x) = x + 5
(f ÷ g)(x) = ⁻ˣ²⁺²⁵/ₓ₊₅
(f ÷ g)(x) = ⁻¹⁽ˣ⁺⁵⁾⁽ˣ⁻⁵⁾/ₓ₊₅
(f ÷ g)(x) = -x + 5
I dont understand the question that you are asking
Answer:
S = 128πx² + 64πx + 8π
Step-by-step explanation:
Suraface area of a cylinder is given by:
S = 2πrh + 2πr²
We know that the height is 3 times as big as the radius, hence:
h = 3r
so we can plug in the new h value and rewrite the S equation as:
S = 2πrh + 2πr²
S = 2πr(3r) + 2πr²
S = 6πr² + 2πr²
S = 8πr²
We're given in the question that the radius is (4x + 1) inches, so plug that into r.
Given: r = 4x + 1
Therefore,
S = 8πr²
S = 8π(4x + 1)²
S = 8π(16x²+8x+1)
S = 128πx² + 64πx + 8π
Answer:
This means that after going around the unit circle once (2π radians), both functions repeat. So the period of both sine and cosine is 2π . Hence, we can find the whole number line wrapped around the unit circle.
Step-by-step explanation:
Answer:
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Step-by-step explanation:
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