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liraira [26]
2 years ago
8

Please help! this is the last one i need and i forgot how to do it!

Mathematics
1 answer:
s2008m [1.1K]2 years ago
3 0

Based on the information, Christian would have $5525.5 of annuity.

<h3>How to calculate the annuity?</h3>

According to given information, the number of coffees per week is 3 then, per month is 3x4 = 12

For each coffee is $4.5. Then monthly expenditure for coffees is 12 x 4.5 = $54

Rate of interest r = 1.6% = 1.6/100 = 0.016 and for monthly compounding r = 0.016/12 = 0.00133

n = number of payments = 8 x 12 = 96

We can use the formula for finding the future value as below

FV = C x [ ( 1 + r )n-1 ] / ( r )

FV = 54 x [ ( 1 + 0.00133 )96 – 1 ] / (0.00133)

= 54 x [ (1.13609 - 1)] / (0.00133)

= 54 x 0.13609 / (0.00133)

= 54 x 102.3233

= 5525.5

Therefore Christian would have $5525.5 of annuity.

Learn more about annuity on:

brainly.com/question/5303391

#SPJ1

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A study of 420 comma 000 cell phone users found that 134 of them developed cancer of the brain or nervous system. Prior to this
Vesnalui [34]

Answer: (0.00306,0.00334)

Step-by-step explanation:

Given : Sample size : n= 420000

The number of users developed cancer of the brain or nervous system =134

Then , the proportion of users developed cancer of the brain or nervous system :

p=\dfrac{134}{420000}\approx0.0032

Significance level : 1-0.90=0.1

Critical value : z_{\alpha/2}=1.645

The confidence interval for population proportion is given by :-

p\ \pm\ z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}\\\\=0.0032\pm (1.645)\sqrt{\dfrac{(0.0032)(1-0.0032)}{420000}}\approx0.0032\pm0.00014\\\\=(0.00306,0.00334)

Hence, the 90​% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system is (0.00306,0.00334).

4 0
3 years ago
7. Jennifer is 6 years older than Sue. In 4 years, she will be twice as old as Sue was 5 years ago. Find their ages
makvit [3.9K]

Answer: Sue is 20 and Jennifer is 26

Step-by-step explanation:

Let's say that J=Jennifer's age now and S=Sue's age now.

We know that:

J=S+6

Because Jennifer is 6 years older than Sue.

We also know that when Jennifer is 4 years older (J+4), she will be twice as old as Sue was 5 years from now (S-5).

So we get the following equation from that information:

J+4=2(S-5)

So we have the two equations:

J+4=2(S-5)

J=S+6

Let's substitute J=S+6 into the first equation (note that RHS means Right Hand Sie and LHS means Left Hand Side):

(S+6)+4=2(S-5)

S+10=2S-10 [Add 6+4 on the RHS, and distribute on the LHS]

S=2S-20 [Subtract 10 from both sides]

-S=-20 [Subtract 2S from both sides]

S=20 [Divide both sides by -1]

So we know S, which is Sue's age, is 20. So Sue is no 20 years old.

Finding Jennifer's age now is simple. We know Jennifer is 6 years older than Sue, and Sue is 20, so Jennifer is 26 years old.

4 0
2 years ago
It cost 5 dollars for a child ticket and 8 dollars for a adult ticket. Total tickets sold were 110 bringing in 820 dollars? How
omeli [17]

Number of child tickets bought is 20

<h3><u>Solution:</u></h3>

Given that It cost 5 dollars for a child ticket and 8 dollars for a adult ticket

cost of each child ticket = 5 dollars

cost of each adult ticket = 8 dollars

Let "c" be the number of child tickets bought

Let "a" be the number of adult tickets bought

Total tickets sold were 110 bringing in 820 dollars

<em>Number of child tickets bought + number of adult tickets bought = 110</em>

c + a = 110 ----- eqn 1

<em><u>Also we can frame a equation as:</u></em>

Number of child tickets bought x cost of each child ticket + number of adult tickets bought x cost of each adult ticket = 820

c \times 5 + a \times 8 = 820

5c + 8a = 820 -------- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "c" and "a"

From eqn 1,

a = 110 - c  ------ eqn 3

Substitute eqn 3 in eqn 2

5c + 8(110 - c) = 820

5c + 880 - 8c = 820

-3c = - 60

c = 20

Therefore from eqn 3,

a = 110 - 20 = 90

a = 90

Therefore number of child tickets bought is 20

8 0
3 years ago
If you have 18 students and all are paired up at least once how many projects in the year
KatRina [158]
It would be 9 because you get half the number of projects because 18 students are partners and if you divide that you would have 9 groups of 2 and if you multiply that by the number of projects you would get the number of projects (ex:18 dividend by 2 it's 9 then if there is three projects assigned you multiply 9 by 3 to get 27 projects got it?
4 0
3 years ago
Read 2 more answers
And those... sorryyyyyy!:(
sasho [114]

Answer:

F: 18

Step-by-step explanation:

find total amount of points

43 + 7 = 50

subtract half of 50 to find the midpoint

43 - 25

18

L = 18

3 0
3 years ago
Read 2 more answers
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