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N76 [4]
3 years ago
13

In 2009, the world's largest pumpkin weighed 784 kilograms. An average-sized pumpkin weighs 5,000 grams. The 2009 world-record p

umpkin weighs _____ kilograms more than an average-sized pumpkin. (Write your answer as a numeral.)
Mathematics
1 answer:
kozerog [31]3 years ago
3 0
5,000 grams = 5kg

784 - 5 = 779kg

The 2009 world record pumpkin weighs 779kg more than the average sized pumpkin.
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Three apples and twice as many oranges add up to one half the number of cherries in a fruit basket. how many cherries are there?
posledela
So, there are 3 Apples. Oranges = 2 * 3 Apples = 6 Oranges.
The sum of the number of Oranges and Apples represent half of the Cherries.
Mathematically speaking, o + a = 1/2 c <=> 3 + 6 = 1/2c. => c=18.
So there are 18 Cherries.
5 0
3 years ago
25 POINTS!!!
PilotLPTM [1.2K]

Answer:

i think its the 3erd one... im giveing a estimate because of that one dude. lol

Step-by-step explanation:

<u><em>im so so so so sorry if its wrong!!!</em></u>

6 0
3 years ago
Read 2 more answers
Help with finals please <br> !! I will make you brainliest! Please
makkiz [27]

Answer:

angle a + 40 = 180 (linear pair)

a = 180- 40

a = 140

8 0
3 years ago
What's the approximate area of a segment of a circle with a height 6 m and the length of the chord is 20 m? Round your answer to
yuradex [85]
Hello!

The Correct Answer to this would be 100%:

Option "85.4".

(Work Below)

Given:
height = 6m
chord = 20 m

We need to find the radius of the circle.

20 m = 2 √ [ 6m( 2 x radius - 6 m ) ] 
20 m / 2 = 2 √[ 6m( 2 x radius - 6 m ) ] / 2 
10 m = √ [ 6m( 2 x radius - 6 m ) ] 
(10 m)² = √[ 6m( 2 x radius - 6 m ) ] ² 
100 m² = 6 m( 2 x radius - 6 m ) 
100 m² = 12 m x radius - 36 sq m 
100 m² + 36 m² = 12 m x radius - 36 m² + 36 m² 
136 m² = 12 m x radius 
136 m² / 12 m = 12 m x radius / 12 m 
<span>11.333 m = radius 
</span>
the area beneath an arc: 

Area = r² x arc cosine [ ( r - h ) / r ] - ( r - h ) x √( 2 x r x h - h²<span> ). 
</span>
r² = (11.333 m)² = 128.444 m² 
r - h= 11.333 m - 6 m = 5.333 m 
r * h = 11.333 m x 6 m = 68 m²

Area = 128.444 m² x arc cosine [ 5.333 m / 11.333 m ] - 5.333 m x √[ 2 x 68 m² - 36 m² ] 

Area = 128.444 m² x arc cosine [ 0.4706 ] - 5.333 m x √ [ 100m² ] 

Area = 128.444 m² x 1.0808 radians - 5.333 m x 10 m 

Area = 138.828 m² - 53.333 m² 

Area = 85.4 m<span>²
</span>

Hope this Helps! Have A Wonderful Day! :)


And as Always...

7 0
3 years ago
(Look at screenshot)
PilotLPTM [1.2K]

#a

H(0)

It refers to y value on graph when x is 0

So here it refers to y intercept

  • y intercept (0,5)

Hence

  • H(0)=5

#b

Observe the graph

y intercept is not 0 so it's not true

#3

Domain is set of x values in graph

  • [0,oo)

#4

Range is set of y values on graph

  • [5,50]
4 0
2 years ago
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