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mixas84 [53]
2 years ago
9

the sum of two numbers is two. Their differences is one. Set up a system and then solve it to find the smaller of the two number

s
Mathematics
2 answers:
Andru [333]2 years ago
6 0

Answer:

Answer:8 and 4. Explanation: Let the 2 numbers be x and y with x > y. ⇒x+y=12→(1)←sum of 2 numbers. ⇒x−y=4→(2)← difference of numbers.

Step-by-step explanation: Let the 2 numbers be x and y with x > y. ⇒x+y=12→(1)←sum of 2 numbers. ⇒x−y=4→(2)← difference of numbers.

Step-by-step explanation:

I copied the first guys answer

Verizon [17]2 years ago
4 0

Answer:8 and 4. Explanation: Let the 2 numbers be x and y with x > y. ⇒x+y=12→(1)←sum of 2 numbers. ⇒x−y=4→(2)← difference of numbers.

Step-by-step explanation: Let the 2 numbers be x and y with x > y. ⇒x+y=12→(1)←sum of 2 numbers. ⇒x−y=4→(2)← difference of numbers.

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1 foot = \frac{1}{3} yard

1431 ÷ 3 = 477 yards
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3 years ago
The dimensions of a right rectangular prism are 1.5 cm,0.5 cm and 2. 25 cm.
Mariulka [41]
The volume of the triangle will be V=1.6875 cm^3
6 0
2 years ago
What is the unit rate for 875.52 kilometers in 38.4 hours? Enter your answer, as a decimal, in the box.
serious [3.7K]
We are given:
number of kilometers = 875.52 km
time = 38.4 hours

We need to calculate the unit rate, which means that we need to find the number of kilometers in one hour.
To do so, we will simply divide the total number of kilometers by the total time as follows:
unit rate = 875.52 / 38.4 = 22.8 km/hour
8 0
3 years ago
Read 2 more answers
A random sample of 36 students at a community college showed an average age of 25 years. Assume the ages of all students at the
Pavel [41]

Answer:

98% confidence interval for the average age of all students is [24.302 , 25.698]

Step-by-step explanation:

We are given that a random sample of 36 students at a community college showed an average age of 25 years.

Also, assuming that the ages of all students at the college are normally distributed with a standard deviation of 1.8 years.

So, the pivotal quantity for 98% confidence interval for the average age is given by;

             P.Q. = \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = sample average age = 25 years

            \sigma = population standard deviation = 1.8 years

            n = sample of students = 36

            \mu = population average age

So, 98% confidence interval for the average age, \mu is ;

P(-2.3263 < N(0,1) < 2.3263) = 0.98

P(-2.3263 < \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < 2.3263) = 0.98

P( -2.3263 \times {\frac{\sigma}{\sqrt{n} } < {\bar X - \mu} < 2.3263 \times {\frac{\sigma}{\sqrt{n} } ) = 0.98

P( \bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} } < \mu < \bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} } ) = 0.98

98% confidence interval for \mu = [ \bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} } , \bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} } ]

                                                  = [ 25 - 2.3263 \times {\frac{1.8}{\sqrt{36} } , 25 + 2.3263 \times {\frac{1.8}{\sqrt{36} } ]

                                                  = [24.302 , 25.698]

Therefore, 98% confidence interval for the average age of all students at this college is [24.302 , 25.698].

8 0
3 years ago
The loudness, L, measured in decibels (Db), of a sound intensity, I, measured in watts per square meter, is defined as mc024-1.j
Alex Ar [27]
We have the given I = 10^-1 and I₀ = 10^-12.

Simply plugging in the values to the equation, we have:
L = 10log(10^-1/10^-12)
L = 110 Db

The answer is D.

(I used a scientific calculator in solving for L).
8 0
3 years ago
Read 2 more answers
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