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kupik [55]
2 years ago
10

I’m too lazy to do all of this and I’m also a little confused on it, and I also have more hw besides this one, so ima need all t

he help I can get. WHOEVER ANSWERS THE MOST GETS BRAINLIEST

Mathematics
2 answers:
Oliga [24]2 years ago
6 0

Answer:

14. 70% of 20000 is 14000. 25% of 14000 is 3500. 3500 students applied.

15. The percentage of 4000 that 2600 equates to would be 65%.

16. 4% of 33000 is 1320.

16b. Double of 1320 is 2640.

17. 3% of 110 + 275 + 200 + 145 is 21.9. 97% of that is 711.1. Total is 730.

18. There are 1656 men working. Total of 1380 + 1656 is 3036. Two ways to solve this are:

Honestly I can't think of two. Sorry, my brain is completely fried today.

19. 760 in sales commissions to meet the wage amount.

20. The agency gets 21010. 30% of that is 6303. This is explained by owning a calculator or simple value elimination.

mr Goodwill [35]2 years ago
5 0
I got 100% on my test today yay
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The variable z is directly proportional to x. When x is 11, z has the value 44. What is the value of z when x = 21?
dimulka [17.4K]

Directly proportional, both increase/decrease, Multiple k(constant you needed to solve for)..

Inversely --one increases as the other decreases, increase the denominator & fraction gets smaller.... So

Problem:

Dirextly to X (× by X)

Inversely to Y, (÷ by Y)

Z= k X/Y

Solve, working backwards: Z =5 becomes

5 = k (X) ÷ (Y). And

X=15 and Y =9 becomes

5= k(15)/(9). Undo ÷9, ×9 both sides

45= k(15). Now undo ×15 by ÷15 both sides

45/15 = 3. So k=3, (also called your constant of variation)....and your Equation/Proportion becomes...

Z = 3X/Y

Use the new #s.... X=23, Y=14

Z= 3×23÷14 = 69/14. If they want spirochete answer divide and round to corresponding # if decimals

4 0
3 years ago
a plumber laying 500 meters of drain pipe required 20 men of working for 10 days . What length in meters would be laid by 50 men
belka [17]

Answer:

500 meters =20men =10days

To get the factor 500/(20*10)= 5/2 meters/day

For 50 men and 5days we don't know the meters

So we go by 50*(5/2)*5 =625meters

8 0
3 years ago
The sum of 2 numbers is 46. One number is 12 more than the other. What are the numbers?
harkovskaia [24]

Answer:

two numbers are 29 and 17

Step-by-step explanation:

let the number be x

12+x+x=46

2x=46-12

x=34/2

x=17

another number is 12+x

12+17

29

5 0
3 years ago
Read 2 more answers
Uninhibited growth can be modeled by exponential functions other than​ A(t) ​=Upper A 0 e Superscript kt. For ​ example, if an i
laila [671]

The question is incomplete. Here is the complete question.

Uninhibited growth can be modeled by exponential functions other than A(t)=A_{0}e^{kt}. for example, if an initial population P₀ requires n units of time to triple, then the function P(t)=P_{0}(3)^{\frac{t}{n} } models the size of the population at time t. An insect population grows exponentially. Complete the parts a through d below.

a) If the population triples in 30 days, and 50 insects are present initially, write an exponential function of the form P(t)=P_{0}(3)^{\frac{t}{n} } that models the population.

b) What will the population be in 47 days?

c) When wil the population reach 750?

d) Express the model from part (a) in the form A(t)=A_{0}e^{kt}.

Answer: a) P(t)=50(3)^{\frac{t}{30} }

              b) P(t) = 280 insects

              c) t = 74 days

             d) A(t)=50e^{0.037t}

Step-by-step explanation:

a) n is time necessary to triple the population of insects, i.e., n = 30 and P₀ = 50. So, Exponential equation for growth is

P(t)=50(3)^{\frac{t}{30} }

b) In t = 47 days:

P(t)=50(3)^{\frac{t}{30} }

P(47)=50(3)^{\frac{47}{30} }

P(47)=50(3)^{1.567}

P(47) = 280

In 47 days, population of insects will be 280

c) P(t) = 750

750=50(3)^{\frac{t}{30} }

\frac{750}{50}=(3)^{\frac{t}{30} }

(3)^{\frac{t}{n} }=15

Using the property <u>Power</u> <u>Rule</u> of logarithm:

log(3)^{\frac{t}{30} }=log15

\frac{t}{30}log(3)=log15

t=\frac{log15}{log3} .30

t = 74

To reach a population of 750 insects, it will take 74 days

d) To express the population growth into the described form, determine the constant k, using the following:

A(t) = 3A₀ and t = 30

A(t)=A_{0}e^{kt}

3A_{0}=A_{0}e^{30k}

3=e^{30k}

Use Power Rule again:

ln3=ln(e^{30k})

ln3=30k

k=\frac{ln3}{30}

k = 0.037

Equation for exponential growth will be:

A(t)=50e^{0.037t}

3 0
3 years ago
Multiply<br> 5x107 * 3x105
djverab [1.8K]

Answer:

the first on 5×107=535 the second one 3×105=315

8 0
3 years ago
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