Answer:Solution
(
−
1
)
(
+
2
)
(
+
5
)
(
x
−
1
)
(
x
+
2
)
(
x
+
5
)
(x−1)(x+2)(x+5)
Step-by-step explanation:
How to solve your problem
3
+
6
2
+
3
−
1
0
x
3
+
6
x
2
+
3
x
−
10
x3+6x2+3x−10
Grouping
1
Find one factor
Factor by grouping
Factor by grouping
Factor by grouping
Answer:
Isabelle is correct, its enough to find each angle. We know in a triangle theres 180 degrees expecially in straight lines, in NP and PQ there is two right angles making them similar.
Hey there!
<u>Opposite sides are congruent:</u>
all of them
<u>opposite angles are congruent</u>
rectangle and square
<u>all sides are congruent</u>
rhombus and square
<u>diagonals congruent:</u>
rectangle, rhombus, and square
<u>diagonals are perpendicular</u>
square and rhombus
Have a terrificly amazing day!
If you need anything else just tell me but I need more info for the
Answer
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
<span> x^2-14*x+31-(63)=0 </span><span>x = 16
</span>
