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Leya [2.2K]
3 years ago
12

Please help, i cant anymore

Mathematics
2 answers:
IgorLugansk [536]3 years ago
8 0

Step-by-step explanation:

(x+2)^2 + (y-3)^3 = 4

the #'s in the () are your center coordinates

Do the opposite signs to get (-2, 3)

Then take the square root of 4 to get your radius of 2

Then plot the center and create the circle

pic shown below:

skad [1K]3 years ago
4 0

Answer:

See below

Step-by-step explanation:

The center of the circle is (-2, 3) and the radius is \sqrt{4} = 2

I can't graph the circle for you, so go find (-2, 3), go 2 units to the left, right, up and down and put a point at those places.  Then sketch the circle.  OK?

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Total volume is volume of cylinder+volume of cone
Volume of cylinder=pi*r^2*h
V=pi*6^2*14
V=1582.56
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V=226.08
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3 years ago
Maddie buys 3 sodas for $2 each. she pays with cash and receives $4 in change. write an equation that can be used to find d, the
Ierofanga [76]
3×2=6+4=d the 3×2 is how much the cost is and 6+4 is 10 so she paid 10 dollars
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IS 419.10 GREATER THAN 419.099
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A number has an absolute value equal to 13
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4 0
3 years ago
Show work <br> only do those <br> 32,34,36,38,40
Free_Kalibri [48]

Answer:  see below

<u>Step-by-step explanation:</u>

32)\quad \dfrac{3}{5}(x-12)>x-24

        3(x - 12) > 5(x - 24)

        3x - 36 > 5x - 120

      <u> -5x       </u>   <u>-5x         </u>

        -2x - 36 >      -120

        <u>      +36</u>      <u>    +36 </u>

        -2x        >       -84

   <u>  ÷ -2        </u> ↓    <u>   ÷ -2  </u>

             x      <       42

Graph:   ←------------o

                             42

34)   6[5y - (3y - 1)] ≥ 4(3y - 7)

        6[5y - 3y + 1] ≥ 4(3y - 7)

        6{2y + 1]        ≥ 4(3y - 7)

         12y + 6        ≥ 12y - 28

        <u>-12y            </u>    <u>-12y       </u>

                  6        ≥         -28

                        TRUE  so the solution is All Real Numbers

Graph:   ←-----------------------→

36)   BC  +  AC      > AB

         4    + 8 - AB > AB

                12 - AB  > AB

       <u>             +AB  </u>  <u>+AB </u>

                12          > 2AB

      <u>         ÷2        </u>    <u>÷2     </u>

                 6           >  AB

                         AB < 6

38)\quad \dfrac{1}{2}(y-16)\geq y+2\quad ;\text{claim}\ y\leq 20

Check: let y = 16

           then \frac{1}{2}(16 - 16) ≥ 16 + 2

                            0    ≥ 18

                            FALSE  so the claim is wrong

40) question not provided in the image so I cannot give a solution.

7 0
3 years ago
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