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2 years ago

.−3(4x + 3) + 4(6x + 1) = 43 What is the solution?

Mathematics

1 answer:

maks197457 [2]2 years ago

6 0

Answer:

x = 4

Step-by-step explanation:

After you simplify the left side by eliminating parentheses and collecting terms, you have a 2-step linear equation.

-3(4x +3) +4(6x +1) = 43 . . . . . . given

-12x -9 +24x +4 = 43 . . . . . eliminate parentheses

12x-5 = 43 . . . . . . . . . . . collect terms (now a 2-step equation)

12x = 48 . . . . . . . . . . step 1, add the opposite of the unwanted constant

x = 4 . . . . . . . . . . . step 2, divide by the coefficient of x

The solution is x = 4.

<em>Check</em>

-3(4·4 +3) +4(6·4 +1) = 43 . . . . substitute for x

-3(16 +3) +4(24 +1) = 43

-3(19) +4(25) = 43

-57 +100 = 43 . . . . . true

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The graph of F(x), shown below, resembles the graph of G(x) x2, but it has

Bingel [31]

Correct answer is: F(x)=-x^2-3

Step-by-step explanation:

We are given a function:

The graph of is also shown in the given question figure.

It is a parabola with vertex at (0,0).

Sign of is positive, that is why the parabola opens up.

General equation of parabola is given as:

Here, in G(x), a = 1

Vertex (h,k) is (0,0).

As seen from the question figure,

The graph of F(x) opens down that is why it will have:

Sign of as negative. i.e.

And vertex is at (0,-3)

Putting the values of a and vertex coordinates,

Hence, the equation of parabola will become:

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3 years ago

See image for question.

kotegsom [21]

Answer:

(a)

<u>Sample space:</u>

1*1, 1*2, 1*3, 1*4,
2*1, 2*2, 2*3, 2*4,
3*1, 3*2, 3*3, 3*4,
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Total 16 outcomes

(b)

(i) P(even) = 12/16 = 3/4
(ii) P(3x) = 7/16
(iii) P(perfect square) = 4/16 = 1/4

(a) <u>Sample space:</u>

1T, 1H, 2T, 2H, 3T, 3H, 4T, 4H

Total 8 outcomes

(b)

(i) 1T, 3T

P(T and odd) = 2/8 = 1/4

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P(H and square) = 2/8 = 1/4

(iii) 1H, 2H, 3H, 4H

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3 years ago

What is the standard for of (1 7i)(3-i)?

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3 years ago

The equation of a circle is given below.

BARSIC [14]

<u>Given</u>:

The equation of the circle is $x^2+(y+4)^2=64$

We need to determine the center and radius of the circle.

<u>Center</u>:

The general form of the equation of the circle is $(x-h)^2+(y-k)^2=r^2$

where (h,k) is the center of the circle and r is the radius.

Let us compare the general form of the equation of the circle with the given equation $x^2+(y+4)^2=64$ to determine the center.

The given equation can be written as,

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Comparing the two equations, we get;

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Therefore, the center of the circle is (0,-4)

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Let us compare the general form of the equation of the circle with the given equation $x^2+(y+4)^2=64$ to determine the radius.

Hence, the given equation can be written as,

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Comparing the two equation, we get;

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3 years ago

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Allushta [10]

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3 years ago

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