The given information is,
→ a = -8
→ b = -7
→ c = 6
Let's verify the problem,
→ (a+b) + c = a+ (b+c)
→ (-8 - 7) + 6 = -8 + (-7 + 6)
→ -15 + 6 = -8 - 1
→ -9 = -9
→ [ LHS = RHS ]
Hence, it is equal and verified.
Answer:
The product is:
![\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D15%20%26%2014%5C%5C-1%20%26%209%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
For this problem you need to multiply the first row only for the two first column of the others matrix and get the desired result:
![\left[\begin{array}{ccc}1&3&1\\-2&1&0\end{array}\right] \times \left[\begin{array}{cc}2&-2\\3&5\\4&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%261%5C%5C-2%261%260%5Cend%7Barray%7D%5Cright%5D%20%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-2%5C%5C3%265%5C%5C4%261%5Cend%7Barray%7D%5Cright%5D)

So the value of the element in the position
is 15

So the value of the element in the position
is 14
Then with these two values you can determinate the result matrix.
![\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D15%20%26%2014%5C%5C-1%20%26%209%5Cend%7Barray%7D%5Cright%5D)
Answer: 990.9 .9+ 990
Step-by-step explanation: you have to do order of operations witch is PEMDAS so you do Parentheses then exponents multiplication or division and addition or subtraction but you do it depending how it starts and in this case you have to subtract the 2 numbers and then add the answer of the multiplication problem
Answer:
for me the answer was c not sure if you will get it correct but again the answer for me was C
Step-by-step explanation:
Answer: 36
Step-by-step explanation:
36
6: 6,12,18,24,30,36