Could y’all help me out with this?
1 answer:
Answer:
M' (5,-1)
D' (5,1)
A' (3,4)
W' (4,-1)
Step-by-step explanation:
We want to find the coordinates of Quadrilateral MDAW with vertices M(-1, 5), D(1,5), A(4,3), and W(-1,4) after a reflection across y = x.
We can find these coordinates by following the following rule:
Reflection over y = x rule : ( x , y ) ---> ( y , x )
Explanation of rule: Simply swap the places of the x and y values.
Applying rule to given coordinates:
M(-1,5) -----> swap x and y values -----> M'(5,-1)
D(1,5) ----> swap x and y values -----> D'(5,1)
A(4,3) -----> swap x and y values -----> A'(3,4)
W(-1,4) -----> swap x and y values -----> W'(4,-1)
So the coordinates of Quadrilateral MDAW after a reflection over the y = x line are M'(5,-1) , D'(5,1) , A'(3,4) , W'(4,-1)
For more validation, refer to the attached image
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Answer:
Option B , C , E are characteristics of the function .
Step-by-step explanation:
Given : function f(x)=2(x-4)^5.
To find : What are the characteristics of the function .
Solution : We have given that f(x)=2.
By the End Point behavior : if the degree is even and leading coefficient is odd of polynomial of function then left end of graph goes down and right goes up.
Since , Option E is correct.
It has degree 5 therefore, function has 5 zeros and atmost 4 maximua or minimum.
Option C is also correct.
By transformation rule it is vertical stretch and shift to right (B )
Therefore, Option B , C , E are characteristics of the function .