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kati45 [8]
3 years ago
11

Could y’all help me out with this?

Mathematics
1 answer:
Aneli [31]3 years ago
4 0

Answer:

M' (5,-1)

D' (5,1)

A' (3,4)

W' (4,-1)

Step-by-step explanation:

We want to find the coordinates of Quadrilateral MDAW with vertices M(-1, 5), D(1,5), A(4,3), and W(-1,4) after a reflection across y = x.

We can find these coordinates by following the following rule:

Reflection over y = x rule : ( x , y ) ---> ( y , x )

Explanation of rule: Simply swap the places of the x and y values.

Applying rule to given coordinates:

M(-1,5) -----> swap x and y values -----> M'(5,-1)

D(1,5) ----> swap x and y values -----> D'(5,1)

A(4,3) -----> swap x and y values -----> A'(3,4)

W(-1,4) -----> swap x and y values -----> W'(4,-1)

So the coordinates of Quadrilateral MDAW  after a reflection over the y = x  line are M'(5,-1) , D'(5,1) , A'(3,4) , W'(4,-1)

For more validation, refer to the attached image

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Suppose you take a 30-question, multiple-choice test, in which each question contains 4 choices: A, B, C, and D. If you randomly
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Answer:

(a) The probability you pass the exam is 0.0000501.

(b) The expected number of correct guesses is 7.5.

(c) The standard deviation is 2.372.

Step-by-step explanation:

We are given that you take a 30-question, multiple-choice test, in which each question contains 4 choices: A, B, C, and D. And you randomly guess on all 30 questions.

Since there is an assumption of only 1 correct choice out of 4 which means the above situation can be represented through binomial distribution;

P(X =x) = \binom{n}{r}\times p^{r}\times (1-p)^{n-r}  ; x = 0,1,2,3,......

where, n = number of trials (samples) taken = 30

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           p = probbaility of success which in our question is the probability

                 of a correct answer, i.e; p = \frac{1}{4} = 0.25

Let X = Number of questions that are correct

So, X ~ Binom(n = 30 , p = 0.25)

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= \binom{30}{18}\times 0.25^{18}\times (1-0.25)^{30-18} + \binom{30}{19}\times 0.25^{19}\times (1-0.25)^{30-19} +.......+ \binom{30}{29}\times 0.25^{29}\times (1-0.25)^{30-29} + \binom{30}{30}\times 0.25^{30}\times (1-0.25)^{30-30}

= 0.0000501

(b) The expected number of correct guesses is given by;

  Mean of the binomial distribution, E(X) =  n \times p

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(c) The standard deviation of the binomial distribution is given by;

      S.D.(X)  =  \sqrt{n \times p \times (1-p)}

                    =  \sqrt{30 \times 0.25 \times (1-0.25)}

                    =  \sqrt{5.625}  =  2.372                

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