Could y’all help me out with this?
1 answer:
Answer:
M' (5,-1)
D' (5,1)
A' (3,4)
W' (4,-1)
Step-by-step explanation:
We want to find the coordinates of Quadrilateral MDAW with vertices M(-1, 5), D(1,5), A(4,3), and W(-1,4) after a reflection across y = x.
We can find these coordinates by following the following rule:
Reflection over y = x rule : ( x , y ) ---> ( y , x )
Explanation of rule: Simply swap the places of the x and y values.
Applying rule to given coordinates:
M(-1,5) -----> swap x and y values -----> M'(5,-1)
D(1,5) ----> swap x and y values -----> D'(5,1)
A(4,3) -----> swap x and y values -----> A'(3,4)
W(-1,4) -----> swap x and y values -----> W'(4,-1)
So the coordinates of Quadrilateral MDAW after a reflection over the y = x line are M'(5,-1) , D'(5,1) , A'(3,4) , W'(4,-1)
For more validation, refer to the attached image
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Answer:
66.42° between height and hypotenuse
23.58° between base and hypotenuse
Step-by-step explanation:
Using the concept of cosine and sine, we know that cosine of an angle is equal to the adjacent divided by hypotenuse.
Similarly, sine of an angle is given by opposite divided by hypotenuse
Tangent is given by opposite divided by adjacent
In rhis case, we use cosine
Therefore, the angle between the hypotenuse and height is 66.42°
To find the angle between base and hypotenuse, since it is a right angle triangle then the other angle will be 90-66.42=23.58°