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AnnZ [28]
2 years ago
11

Sheronda travels around the world for her job. She traveled 1,356 miles last year. This year, her plans will require her to trav

el 18 times as many miles as last year. How many miles will Sheronda travel this year?
Mathematics
2 answers:
Gala2k [10]2 years ago
6 0

Answer:

24408

Step-by-step explanation:

Multiply every number by 8, then multiply every number by 10.

Lelu [443]2 years ago
6 0

Answer:

24,408

Step-by-step explanation:

multiply 1,356 by 18

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A group of 3 friends spends a total of $17.25 for brunch at a restaurant before tax and tip. Everyone orders the same thing: scr
liubo4ka [24]

Answer:

17.25/3 = 5.75

Step-by-step explanation:

You divide 17.25 by 3.

It equals 5.75. Each friend has 5.75 on spend on brunch.

Toast is $1. Orange Juice is $1.75. Eggs are $2.

Hope this helps.

3 0
3 years ago
*trigonometry and area.*
soldier1979 [14.2K]

Answer:

<u>The correct answer is that the area of the regular octagon is 309 cm²</u>

Step-by-step explanation:

There are several formulas for calculating the area of a regular octagon. We will use this one for solving this question because it does not require additional information .

Area = (2 * s²)/tan 22,5°

s = 8 cm

Replacing with the real values, we have:

Area = (2 * 8²)/tan 22,5°

Area = 2 * 64/0.4142

Area = 128/0.4142

<u>Area = 309 cm² (Rounding to the nearest tenth)</u>

6 0
3 years ago
I need help please and thank you
Debora [2.8K]
1. The variable A added to the sum of the variable D and 6
2. 10 added to b multiplied by 2
4 0
3 years ago
Read 2 more answers
How do I solve this equation?
Gnom [1K]

2x(4-x)^{-1/2}-3(4-x)^{1/2}=(4-x)^{-1/2}\bigg(2x-3(4-x)\bigg)

We effectively rewrite the equation as

\dfrac{5x-12}{(4-x)^{1/2}}=0

In order for the LHS to be defined, we need to restrict 4-x>0, or x. Now, the LHS will vanish when the numerator is 0, which happens for

5x-12=0\implies5x=12\implies x=\dfrac{12}5

This value is indeed smaller than 4, so the solution is x=\dfrac{12}5.

8 0
3 years ago
Describe a scenario where the function value exists at x=c, but the limit does not exist.
Vikki [24]

The scenario can be described using a piecewise function like:

f(x) = 1/x                  if  x < c.

f(x) = x                    if   x = c

f(x) = 1/(x + 73)       if x > c.

<h3>When the value exists but the limit does not?</h3>

Remember that the limit only exists if the limit from left and the limit from the right give the same value.

Then, we can just define a piecewise function of the form:

f(x) = 1/x                  if  x < c.

f(x) = x                    if   x = c

f(x) = 1/(x + 73)       if x > c.

Clearly, this is not a continuous function.

Notice that:

f(c) = c.\\\\ \lim_{x \to c^{-}} f(x) = 1/c\\\\ \lim_{x \to c^{+}} f(x) = 1/(c + 73)

So the limits from left and right are different, then:

\lim_{x \to c^{}} f(x)

Does not exist.

If you want to learn more about limits:

brainly.com/question/5313449

#SPJ1

6 0
2 years ago
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