Answer:
Idk if its multiple choice but you can do 1 of 2 ways theres using distance formula =√(5-3)sq+(1-4)sq
=√4+9
=√13 <--
or
3.6 units
Given: The two points that are P(5,1) and Q(3,4).
To find: The distance between these two points.
Solution: It is given that there are two points that are P(5,1) and Q(3,4).
The distance between these two points can be found out as using the distance formula that is: 3.6
Thus, the distance between the given two points is 3.6 units.
So you choose 13 or 3.6 Hope this helps :)
1. First, you must find the constant of variation (k). The problem indicates that t<span>he base of each triangle varies inversely with the height. So, this can be represented as below:
</span>
B=k/H
B is the base of the triangle (B=10).
H is the height of the triangle (H=6).
k is the constant of variation.
2. When you clear "k", you obtain:
B=k/H
k=BxH
k=10x6
k=60
3. Now, you have:
B=60/H
4. You can give any value to "H" and you will obtain the base of the second triangle.
5. If H=12, then:
B=60/H
B=60/12
B=5
6. Therefore, <span>the possible base and height of a second triangle is:
</span>
B=5
H=12
Answer:
D. 314 yds
Step-by-step explanation:
Given:
Diameter = 100 yds
Required;
Circumference of the circle
Solution:
Circumference of circle = πd
Plug in the value
Circumference = π × 100
= 314 yds (nearest whole number)
Answer:
432
Step-by-step explanation:
Answer: he lying dont trust hjim.
Step-by-step explanation:
