Answer:
a. 5,040 ways
b. 210 ways
Step-by-step explanation:
a) We want to pick 4 numbers out of 10 given that orders matter
If orders do matter, it will be a permutation problem
Mathematically;
n P r = n!/(n-r)!
In this case, n is 10 and r is 4
Thus, we have it that;
10 P 4 = 10!/(10-4)! = 5,040
b) if orders do not matter
It will be a combination problem
n C r = n!/(n-r)!r!
n = 10 and r = 4
10 C 4 = 10! /(10-4)!4!
= 210
1) When the denominator equals zero that is a critical point
=> x - 2 = 0 => x = 2.
So x = 2 is a critical point
2) Simplify the numerator to find an expresion of the king p(x) ≥ 0 or p(x) ≤ 0. Where p(x) equals zero you have other(s) critical point(s)
Multiply both terms:
[2x + 5] / [ x - 2] = [x - 1] / [x - 2]
for x ≠ 2 => 2x + 5 = x - 1
=> 2x - x = - 1 - 5
=> x = - 6
Then, the two critical points are x = 2 and x = - 6.
Answer: option B.
You combine like terms which are -10x and 7x and 1 and 37. Then it becomes -3x=36. x would equal to 36/-3, which is -12.
Answer:
All sides will be 11 and all angles will be 90 degrees.
Step-by-step explanation:
As all sides of square are equal. And all angles are right angled.
Hope it helped!!
Answer:
7pq( 2 + 5r)
Step-by-step explanation:
