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GuDViN [60]
3 years ago
7

Need friends do u want a friend?

Mathematics
2 answers:
Pavel [41]3 years ago
6 0
Hey yeah sure we can be friends
sp2606 [1]3 years ago
3 0
I need a brainliest pls
You might be interested in
Solve the inequality.<br><br> 6(x/2 + 4)&gt;9
Airida [17]

6(x/2 + 4)>9

x/2 + 4 > 9/6

x/2 + 4 > 3/2

x/2 > 3/2 - 4

2*(x/2) > 2*(3/2 - 4)

x > 3 - 8

x > - 5

7 0
4 years ago
Find the product please i need it ?
Ipatiy [6.2K]

Answer:a2=5 , a1=1 , a0=3, a5=2 , a4=5 , a3=2 , a6=0 , a10=5 , a9=3 , a8=8 , a7=2

Step-by-step explanation:

63 x 45=2835

5 0
3 years ago
You have prizes to reveal! Go to your game board. *
kari74 [83]

Answer:

y = 1/4x^2 - 4.

Step-by-step explanation:

Vertex for is:

y = a(x - 0)^2 - 4     where a is a constant.

The graph passes through ( -8, 12) so substituting:

12 = a(-8)^2 - 4

12 = 64a - 4

64a = 16

a = 16/64 = 1/4.

So the equation is  y = 1/4x^2 - 4.

4 0
3 years ago
Read 2 more answers
Write the fraction as a decimal. Round to the nearest hundredth, if necessary. <br> 7/8
labwork [276]

Answer:

0.875

Step-by-step explanation:

We know that

7/8

is the same as

7÷8

Then using

Long Division for 7 divided by 8

and rounding to a Max of 3 Decimal Places gives us

=0.875

hope this helps:)sorry if it doesnt

plz give brainliest

4 0
3 years ago
Read 2 more answers
Enter the ordered pair for the vertices for (Ry-axis ○ T(2, 0))(QRST).
zhannawk [14.2K]

Answer:

The answer is:

Q' = (-3, 3)\\\\R' = (-5, -3)\\\\S' = (-2, -2)\\\\T' = (0, 1)\\\\

Step-by-step explanation:

All vertices of its quadrilateral were co-ordinated;  

T(-2, 1), \ Q(1, 3), \ S(0, -2), \ R(3, -3) Therefore, we first undertake the operation correct: T(2, 0) \ QRST, there;

T(2, 0) \ QRST \to  T(-2 + 2, 1), \ Q(1 + 2, 3), \ S(0 + 2, -2), \ R(3 + 2, -3)

T(2, 0) \ QRST\to  T(0, 1), \ Q(3, 3), \ S(2, -2), \ R(5, -3)

A preimage (x, y) will be the image in the next phase R-y-axis reflecting mostly on the y-axis (-x, y)  and we've got it;  

R y-axis (T(0, 1), \ Q(3, 3), \ S(2, -2), \ R(5, -3)) = \ T'(0, 1), \ Q'(-3, 3), \ S'(-2, -2), \ R'(-5, -3)From which we get (Ry-axis \ T(2, 0)) \ (QRST =  T'(0, 1), \  Q'(-3, 3), \ S'(-2, -2),\  R'(-5,-3).

7 0
3 years ago
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