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2 years ago

X+5+4-5=x+54Help !!!

Mathematics

2 answers:

Rzqust [24]2 years ago

8 0

Answer:

0=50

Step-by-step explanation:

Add the numbers +5+4−5=+54x

+{\color{#c92786}{5}}+{\color{#c92786}{4}}{\color{#c92786}{-5}}=x+54

x+5+4−5=x+54

x+{\color{#c92786}{4}}=x+54

x+4=x+54

Subtract

from both sides of the equation

Simplify

Subtract

from both sides of the equation

Simplify

max2010maxim [7]2 years ago

5 0

Simplify both sides of the equation

=>x+5+4−5=x+54

=>x+5+4+−5=x+54

=>(x)+(5+4+−5)=x+54(Combine Like Terms)

=>x+4=x+54

Subtract x from both sides

=>x+4−x=x+54−x

=>4=54

Subtract 4 from both sides

=>4−4=54−4

=>0=50

There are no solutions

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3 years ago

HELP ME ASAP!!!!!!!!

Marina CMI [18]

Answer:

Step-by-step explanation:

1) 30 : 100 = x : 299

x = (30 x 299)/100

x = 89,70 $

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3 years ago

A ferry will safely accommodate 82 tons of passenger cars. Assume that the meanweight of a passenger car is 2 tons with standard

Shalnov [3]

Answer:

The probability that the maximum safe-weight will be exceeded is <u>0.0455 or 4.55%</u>.

Step-by-step explanation:

Given:

Maximum safe-weight of 37 cars = 82 tons

∴ Maximum safe-weight of 1 car (x) = 82 ÷ 37 = 2.22 tons (Unitary method)

Mean weight of 1 car (μ) = 2 tons

Standard deviation of 37 cars = 0.8 tons

So, standard deviation of 1 car is given as:

$\sigma=\frac{0.8}{\sqrt{37}}=0.13$

Probability that maximum safe-weight is exceeded, P(x > 2.22) = ?

The sample is normally distributed (Assume)

Now, let us determine the z-score of the mean weight.

The z-score is given as:

$z=\frac{x-\mu}{\sigma}\\\\z=\frac{2.22-2}{0.13}\\\\z=\frac{0.22}{0.13}=1.69$

Now, finding P(x > 2.22) is same as finding P(z > 1.69).

From the z-score table of normal distribution curve, the value of area under the curve for z < 1.69 is 0.9545.

But we need the area under the curve for z > 1.69.

So, we subtract from the total area. Total area is 1 or 100%.

So, $P(z > 1.69) = 1 - P(z < 1.69)$

$P(z>1.69)=1-0.9545=0.0455\ or\ 4.55\%$

Therefore, the probability that the maximum safe-weight will be exceeded is 0.0455 or 4.55%.

8 0

3 years ago

A carton measures 3 feet by 2 feet by 2 feet. A machine can fill the carton with packing material in 3 seconds. How long would i

True [87]

1) we calculate the volume of the first carton:
volume=length x width x height
volume=3 ft * 2 ft * 2 ft=12 ft³

Therefore:
A machine can fill 12 ft³ in 3 seconds.

2) we calculate the volume of the second carton.
volume=length x width x heigth
volume=4 ft * 5 ft * 6 ft=120 ft³

3) we calculate the time that the machine needs for fill the second carton with packing material by the rule of three.

12 ft³---------------------3 seconds
120 ft³-------------------- x

x=(120 ft³ * 3 seconds) / 12 ft³=30 seconds.

answer: 30 seconds.

5 0

3 years ago

X+5+4-5=x+54Help !!!​

X+5+4-5=x+54Help !!!