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Vanyuwa [196]
2 years ago
12

Find the x-intercepts of the parabola with vertex (1,-108) and y-intercept (0,-105). Write your answer in this form: (X1,y1), (x

2,y2). If necessary, round to the nearest hundredth.​
Mathematics
1 answer:
Stolb23 [73]2 years ago
7 0

Answer:

(7, 0) and (-5, 0)

Step-by-step explanation:

<u>Vertex form</u>

y=a(x-h)^2+k  

(where (h, k) is the vertex)

Given:

  • vertex = (1, -108)

\implies y=a(x-1)^2-108

Given:

  • y-intercept = (0, -105)

\implies a(0-1)^2-108=-105

\implies a(-1)^2=-105+108

\implies a=3

Therefore:

\implies y=3(x-1)^2-108

The x-intercepts are when y = 0

\implies 3(x-1)^2-108=0

\implies 3(x-1)^2=108

\implies (x-1)^2=36

\implies x-1=\pm \sqrt{36}

\implies x=1\pm 6

\implies x=7, x=-5

Therefore, the x-intercepts are (7, 0) and (-5, 0)

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Answer:

x=6

Step-by-step explanation:

A midpoint is the middle point of a line segment, therefore it is equal distances from both ends of the segment.

This means that PQ and QR have the same length. So all we have to do is set each value equal to each other, and then solve for X.

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Step-by-step explanation:

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timama [110]

Answer:

m<1 = 45°  

m<2 = 76°

m<3 = 80°

Step-by-step explanation:

<u>Points to remember</u>

1). Vertically opposite angles are equal

2). Sum of angles of a triangles is 180°

<u>To find the measures of given angles</u>

From the figure we get,

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By using angle sum property <2 + 59 + 45 = 180

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