478×427= 204,106cm
204,106cm - 2041.06m
204,106cm - 20.411m2
Answer:
the last vertex is (8,-8)
the area of the rectangle is 100 square units
Step-by-step explanation:
Answer:
m∠1 + m∠3 = m∠2 + m∠4
Step-by-step explanation:
In the figure attached,
In the given trapezoid if two sides AB and CD are parallel and AD is a transverse,
m∠1 + m∠3 = 180°
Similarly, if AB and CD are parallel and BC is a transverse,
m∠2 + m∠4 = 180°
Therefore, m∠1 + m∠3 = m∠2 + m∠4 is the relation between these angles.
Answer:
20 m by 10 m
Step-by-step explanation:
let w be width and l be length , then
2(l + w) = 60 ( divide both sides by 2 )
l + w = 30 ( subtract w from both sides )
l = 30 - w → (1)
lw = 200 → (2)
Substitute l = 30 - w into (2)
w(30 - w) = 200 ← distribute parenthesis on left side
30w - w² = 200 ( subtract 200 from both sides )
30w - w² - 200 = 0 ( multiply through by - 1 )
w² - 30w + 200 = 0 ← in standard form
(w - 10)(w - 20) = 0 ← in factored form
Equate each factor to zero and solve for w
w - 10 = 0 ⇒ w = 10
w - 20 = 0 ⇒ w = 20
Substitute these values into (1)
l = 30 - 10 = 20
l = 30 - 20 = 10
dimensions of field is 20 m by 10 m
Answer:
- Parent Function:

- Horizontal shift: right 3 units
- Vertical shift: up 3 units
- Reflection about the x-axis: none
- Vertical strech: streched
Step-by-step explanation:
assume that
is
and
is

The transformation from the first equation to the second equation can be found by finding a,h and k for each equation.

factor a 1 out of the absolute value to make the coefficient of x equal to 1

factor a 2 out of the absolute value to make the coefficient of x equal to 1

find a, h and k for 

the horizontal shift depends on the value of h when
, the horizontal shift is described as:
- the graph is shifted to the left h units
- the graph is shifted to the right h units
the vertical shift depends on the value of k