Let the no be X and Y
acc to ques....
x-y=9 .........1
xy=162 ..........2
substituting value from 1 in 2 we get;
x=9+y
[9+y][y] = 162
y^2+9y = 162
y^2 + 9y - 162=0
y^2 + 18y - 9y - 162=0
y[y+18] + 9[y+18]=0
[y+9][y+18}
y= -9.................................3
y= -18......................................4
case 1 :
y= -9
x = 9-9=0
case 2:
y= -18
x= 9-18 = -9
Answer:
n>3
Step-by-step explanation:
HOPE THIS HELPED IF YOU WANT I CAN HELP YOU IF THERES ANYMORE.
Equation 1 is
,
Equation 2 is [/tex] 3x-2y = -1 [/tex]
for first equation LCD= 3 *5 = 15 , So we multiply whole equation by 15


Now multiply second equation by -3 , to make the coefficient of y equal and opposite , so that we can apply the elimination method

Add both the equations


Divide both sides by 11

Plug in any one of the equation we get
3(3) -2y = -1
9 - 2y = -1
subtract 9 from both sides
-2y = -10
divide both sides by -2
y=5
So the solution is x= 3 , y= 5
Which means
a. The system is consistent and independent. TRUE
Answer:
w = 18
Step-by-step explanation:
6(33 - w) = 90
33 - w = 15
-w = -18
w = 18