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2 years ago

7

Select all line segment measurements below that could NOT be used to form a triangle. a triangle with the side measurements of 3

, 4, and 6 inches a triangle with the side measurements of 2, 3, and 5 inches a triangle with the side measurements of 3, 3, and 4 inches a triangle with the side measurements of 5, 5, and 5 inches a triangle with the side measurements of 4, 4, and 8 inches O a triangle with the side measurements of 7, 8, and 16 inches......

2 answers:

monitta2 years ago

4 0

A triangle is 5,5,5, but check your answers

KonstantinChe [14]2 years ago

3 0

Answer:

a triangle with the side measurements of 5, 5, and 5 inches

Step-by-step explanation:

a^2+b^2=c^2

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Bill and Joe leave their house at the same time heading in opposite directions. If Bill is driving three times faster than Joe a

Arisa [49]

The problem statement gives you the relationship between their speeds, and it gives you information you can use to find their total speed. You solve this by finding the total speed, then the proportion of that belonging to Bill.

The total speed is (120 mi)/(3 h) = 40 mi/h.

The speed ratio is ...

... Bill : Joe = 3 : 1

so the speed ratio Bill : Total is ...

... 3 : (3+1) = 3:4.

Bill's speed is (3/4)×(40 mi/h) = 30 mi/h.

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3 years ago

One end of a line segment has the coordinates (-6,2). If

CaHeK987 [17]

Answer:

The coordinates of the other end is $(16,2)$

Step-by-step explanation:

Given

$End 1: (-6,2)$

$Midpoint: (5,2)$

Required

Find the coordinates of the other end

Let Midpoint be represented by (x,y);

(x,y) = (5,2) is calculated as thus

$(x,y) = (\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$

So

$x = \frac{x_1 + x_2}{2}$ and $y = \frac{y_1 + y_2}{2}$

Where $(x_1,y_1) = (-6,2)$ and $(x,y) = (5,2)$

So, we're solving for $(x_2,y_2)$

Solving for $x_2$

$x = \frac{x_1 + x_2}{2}$

Substitute 5 for x and -6 for x₁

$5 = \frac{-6 + x_2}{2}$

Multiply both sides by 2

$2 * 5 = \frac{-6 + x_2}{2} * 2$

$10 = -6 + x_2$

Add 6 to both sides

$6 + 10 = -6 +6 + x_2$

$x_2 = 16$

Solving for $y_2$

$y = \frac{y_1 + y_2}{2}$

Substitute 2 for y and 2 for y₁

$2 = \frac{2 + y_2}{2}$

Multiply both sides by 2

$2 * 2 = \frac{2 + y_2}{2} * 2$

$4 = 2 + y_2$

Subtract 2 from both sides

$4 - 2 = 2 - 2 + y_2$

$y_2 = 2$

$(x_2,y_2) = (16,2)$

Hence, the coordinates of the other end is $(16,2)$

3 0

3 years ago

Find the side length of the right triangle missing a=6,b=?,c=10

Makovka662 [10]

B=8. A^2+B^2=C^2. This means 6to the second power plus B to the second power equals10 to the second power. 36+b^2=100. B to the second power equals 64. Square root of 64 is 8, so B equals 8

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3 years ago

What is 20x12? please help! thankss!!

Vanyuwa [196]

240 is the correct answer.

6 0

2 years ago

Read 2 more answers

What is this asking? 8x-4y=12

kkurt [141]

Maybe from the equation of a line from y=mx+c
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8 0

2 years ago