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Anastaziya [24]
2 years ago
10

What is 4.533 rounded to the nearest tenth?

Mathematics
1 answer:
Angelina_Jolie [31]2 years ago
6 0

Answer:

4.5

Step-by-step explanation:

Round to 5 in the tens

hope this helps <3 have an amazing day :)

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What is the inverse of the function f(x) = 2x + 1?
BaLLatris [955]

Answer:

f^{-1} = \frac{x-1}{2}

Step-by-step explanation:

f(x) = 2x+1

<em>Replace it with y</em>

y = 2x+1

<em>Exchange the values of  x and y</em>

x = 2y+1

<em>Solve for y</em>

x = 2y+1

<em>Subtracting 1 from both sides</em>

2y = x-1

<em>Dividing both sides by 2</em>

y = \frac{x-1}{2}

<em>Replace it by </em>f^{-1}

So,

f^{-1} = \frac{x-1}{2}

3 0
3 years ago
Read 2 more answers
-4a &lt;-32 what is the answer
Fiesta28 [93]

Answer:

a > 8

Step-by-step explanation:

Divide by the coefficient of the variable. Since it is negative, the direction of the comparison must be reversed.

(-4a)/(-4) > (-32)/(-4)

a > 8

6 0
3 years ago
Determine wether the function is increasing, decreasing, or constant
evablogger [386]

Answer:

decreasing

Step-by-step explanation:

"Increasing" means the graph is going up from left to right.

"Decreasing" means the graph is going down from left to right.

"Constant" means the graph is "flat" (this is not a technical term) it is keeping the same y value, neither going up nor going down.

What can be super confusing is the

(2.2, 5) mentioned in the question. THIS IS NOT A POINT. It is an interval and points and intervals unfortunately have the same notation sometimes.

An "interval" is a section of the graph, here: FROM 2.2 not including 2.2, TO 5 not including 5. These are like the address on the x-axis. If you look at your graph at 2.2 on the x-axis, it is a peak(relative maximum) and it goes down to the right to where x is 5 where it bottoms out (relative minimum) So on that interval, from 2.2 to 5, the graph is DECREASING.

4 0
2 years ago
In an article regarding interracial dating and marriage recently appeared in a newspaper. Of 1719 randomly selected adults, 311
Bingel [31]

Answer:

Step-by-step explanation:

Hello!

The parameter of interest in this exercise is the population proportion of Asians that would welcome a person of other races in their family. Using the race of the welcomed one as categorizer we can define 3 variables:

X₁: Number of Asians that would welcome a white person into their families.

X₂: Number of Asians that would welcome a Latino person into their families.

X₃: Number of Asians that would welcome a black person into their families.

Now since we are working with the population that identifies as "Asians" the sample size will be: n= 251

Since the sample size is large enough (n≥30) you can apply the Central Limit Theorem and approximate the variable distribution to normal.

Z_{1-\alpha /2}= Z_{0.975}= 1.965

1. 95% CI for Asians that would welcome a white person.

If 79% would welcome a white person, then the expected value is:

E(X)= n*p= 251*0.79= 198.29

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.79*0.21=41.6409

√V(X)= 6.45

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

198.29±1.965*6.45

[185.62;210.96]

With a 95% confidence level, you'd expect that the interval [185.62; 210.96] contains the number of Asian people that would welcome a White person in their family.

2. 95% CI for Asians that would welcome a Latino person.

If 71% would welcome a Latino person, then the expected value is:

E(X)= n*p= 251*0.71= 178.21

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.71*0.29= 51.6809

√V(X)= 7.19

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

178.21±1.965*7.19

[164.08; 192.34]

With a 95% confidence level, you'd expect that the interval [164.08; 192.34] contains the number of Asian people that would welcome a Latino person in their family.

3. 95% CI for Asians that would welcome a Black person.

If 66% would welcome a Black person, then the expected value is:

E(X)= n*p= 251*0.66= 165.66

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.66*0.34= 56.3244

√V(X)= 7.50

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

165.66±1.965*7.50

[150.92; 180.40]

With a 95% confidence level, you'd expect that the interval [150.92; 180.40] contains the number of Asian people that would welcome a Black person in their family.

I hope it helps!

5 0
3 years ago
Solve this system of equations using the ELIMINATION method.
vodka [1.7K]

hope this helps please like and mark as brainliest

4 0
3 years ago
Read 2 more answers
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