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gogolik [260]
3 years ago
9

What is the value of the 6 in 26,249?

Mathematics
2 answers:
Masteriza [31]3 years ago
8 0

Answer:

its in the 1,000 place

Step-by-step explanation:

Artyom0805 [142]3 years ago
6 0

Answer:

what is the value of the 6 in 26,249?

answer:321305

Step-by-step explanation:

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Which of the following is an example of quantitative data? A the player’s number on a baseball uniform B the serial number on a
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Answer:

The number of people in a waiting line is a quantitative data as we can count them.

Step-by-step explanation:

Consider the provided information.

The value of quantitative data can be determined by counting or measuring something.

Now consider the provided options.

The player’s number on a baseball uniform, the serial number on a one-dollar bill and the part number of an inventory item is not a quantitative data because we can't  measure them.

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Lightbulbs of a certain type are advertised as having an average lifetime of 750 hours. The price of these bulbs is very favorab
Katyanochek1 [597]

Answer:

(a) Customer will not purchase the light bulbs at significance level of 0.05

(b) Customer will purchase the light bulbs at significance level of 0.01 .

Step-by-step explanation:

We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected,  and the following information obtained:

Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.

Let Null hypothesis, H_0 : \mu = 750 {means that the true average lifetime is same as what is advertised}

Alternate Hypothesis, H_1 : \mu < 750 {means that the true average lifetime is smaller than what is advertised}

Now, the test statistics is given by;

       T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = 738.44 hours

               s  = sample standard deviation = 38.2 hours

               n = sample size = 50

So, test statistics = \frac{738.44-750}{\frac{38.2}{\sqrt{50} } } ~ t_4_9

                            = -2.14

(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.

(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.

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12% Of 79 Would be 9.48. Hope this helped :)
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