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mixer [17]
3 years ago
14

Need of help thank you whomever.

Mathematics
1 answer:
xxMikexx [17]3 years ago
4 0

Answer:

y=x-2

Step-by-step explanation:

Line them up on a graph and then use each answer choice and see which matches which would be y=x-2

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kondaur [170]
Add 6 to left middle and right
then, divide them all by 3

6 0
3 years ago
Could I get some help please?
slega [8]
Area of a Trapezoid can be defined by:
A = \frac{1}{2} ( b_{1} + b_{2} )(h)  just substitute given information
8.1 = .5( b_{1} +6.7)(1.5)
8.1 = .75(b₁ + 6.7)
8.1 = .75b₁ + 5.025
8.1 - 5.025 = .75b₁
3.075 = .75b₁
\frac{3.075}{.75} = b_{1}
4.1 = b₁
the other base is equal to 4.1
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4 years ago
Boarding Kennel Problem In a boarding kennel, dogs number 12 more than 2 times the number of cats. If there are 75 animals, how
yKpoI14uk [10]

Answer: C.

Step-by-step explanation: It asks how many cats are boarded.

5 0
3 years ago
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Gold has a density of 19.3 g/mL. What is the mass of a 7.5 mL sample of gold?
Zina [86]

Answer:

144.75 g

Step-by-step explanation:

19.3x7.5 = 144.75

3 0
3 years ago
Given circle and circle with radii of 6cm and 4cm respectively.
noname [10]

Solution :

Given that :

The radius of circle A = 6 cm

The radius of circle C = 4 cm

In circle A

\angle EAF = \theta = 140^\circ

The length of arc EF = $2 \pi r \times \frac{\theta}{360^\circ}$

                                   $=2 \times 3.14 \times 6 \times \frac{140^\circ}{360^\circ}$

                                    = 14.653 cm

In circle C

\angle GCH = \theta = 140^\circ

The length of arc GH = $2 \pi r \times \frac{\theta}{360^\circ}$

                                   $=2 \times 3.14 \times 4 \times \frac{140^\circ}{360^\circ}$

                                    = 9.769 cm    

Therefore,

The length of EF is 14.653 cm

The length of GH is 9.769 cm

The length of EF is  1.5 times the length of GH

i.e.                   14.653  = 1.5 x 9.769

                       14.653 = 14.653

Hence proved.

                             

6 0
4 years ago
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