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3 years ago

If f(x) = 3^{2+x}-3f(x)=3

Mathematics

1 answer:

4vir4ik [10]3 years ago

7 0

The answer would be -2.89

To solve this function, the x is replaced with the new value (-4) This means that once simplified it turns into 3^(-2) - 3
Once simplified this value equals -2.89 when rounded

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If a student walked 2 feet straight to the chalk board in 2 seconds and

sergeinik [125]

Answer:

2 feet

Step-by-step explanation:

Displacement at 0 seconds is 0 feet.

Displacement at 2 seconds is 2 feet because it took them 2 seconds to walk 2 feet.

7 0

3 years ago

Simplify the below question.<br><br> Please send the answer with correct explanation.

melisa1 [442]

Answer:

48t^4

Step-by-step explanation:

First you simplify and cross out all the uneeded characters because this is a division equation

Then whatever is left you calculate it

8 0

3 years ago

Read 2 more answers

X - 9 = 21<br><br> What does x =

Slav-nsk [51]

Answer:

x=30

Step-by-step explanation:

You have to isolate for x. This means you need to somehow get x on one side of the equation all alone. In this case it is x-9=21 which means some unknown number x with 9 subtracted from it is equal to 21. When we bring the -9 over to the other side to get the x all alone, we have to switch the sign of the -9 so it becomes +9. This means x=21+9, and if you add that you'll get 30!

5 0

3 years ago

A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40

malfutka [58]

PART A

The given equation is

$h(t) = - 16 {t}^{2} + 40t + 4$

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4$

We add and subtract

$- 16(- \frac{5}{4} )^{2}$

to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4$

We again factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4$

This implies that,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4$

The quadratic trinomial above is a perfect square.

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4$

This finally simplifies to,

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29$

The vertex of this function is

$V( \frac{5}{4} ,29)$

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

$29$

PART B

When the ball hits the ground,

$h(t) = 0$

This implies that,

$- 16 ( t- \frac{5}{4}) ^{2} +29 = 0$

We add -29 to both sides to get,

$- 16 ( t- \frac{5}{4}) ^{2} = - 29$

This implies that,

$( t- \frac{5}{4}) ^{2} = \frac{29}{16}$

$t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }$

$t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}$

$t = \frac{ 5 + \sqrt{29} }{4} = 2.60$

or

$t = \frac{ 5 - \sqrt{29} }{4} = - 0.10$

Since time cannot be negative, we discard the negative value and pick,

$t = 2.60s$

8 0

3 years ago

What is the equivalent to 8 - 4 + 9 X 12

Feliz [49]

Answer:

156

Step-by-step explanation:

8-4= 4+9 = 13 x 12= 156

Hope this helped

4 0

3 years ago