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DerKrebs [107]
3 years ago
8

Find the value of f(-5).

Mathematics
1 answer:
garri49 [273]3 years ago
5 0

Answer:

tion represents this relationship? How many feet will person travel 10 seconds?A person standing on a moving walkway travels 60 feet in 20 seconds. What equation represents this relationship? How many feet will person travel 10 seconds?A person standing on a moving walkway travels 60 feet in 20 seconds. What equation represents this relationship? How many feet will person travel 10 seconds?A person standing on a moving walkway travels 60 feet in 20 seconds. What equation represents this relationship? How many feet will person travel 10 seconds?A person standing on a moving walkway travels 60 feet in 20 seconds. What equation represents this relationship? How many feet will person travel 10 seconds?A person standing on a moving walkway travels 60 feet in 20 seconds. What equation represents this relationship? How many feet will person travel 10 seconds?A person standing on a moving walkway travels 60 feet in 20 seconds. What equation represents this relationship? How many feet will person travel 10 seconds?A person standing on a moving walkway travels 60 feet in 20 seconds. What equation represents this relationship? How many feet will person travel 10 seconds?

Step-by-step explanation:

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Can someone please help me?
makkiz [27]
Second one...................
7 0
3 years ago
Kendra swims 126 miles in 3 days, what is the constant rate that Kendra swims per day? a. 40 miles per day c. 42 miles per day b
Leni [432]

Answer:

c. 42 miles per day

Step-by-step explanation:

From the information given, you can use a rule of three to calculate the constant rate that Kendra swims per day given that she swims 126 miles in 3 days:

3 days → 126 miles

1 day   →        x

x=(1*126)/3=42 miles

According to this, the answer is that Kendra swims 42 miles per day.

5 0
2 years ago
Find the surface area of the solid generated by revolving the region bounded by the graphs of y = x2, y = 0, x = 0, and x = 2 ab
Nikitich [7]

Answer:

See explanation

Step-by-step explanation:

The surface area of the solid generated by revolving the region bounded by the graphs can be calculated using formula

SA=2\pi \int\limits^a_b f(x)\sqrt{1+f'^2(x)} \, dx

If f(x)=x^2, then

f'(x)=2x

and

b=0\\ \\a=2

Therefore,

SA=2\pi \int\limits^2_0 x^2\sqrt{1+(2x)^2} \, dx=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx

Apply substitution

x=\dfrac{1}{2}\tan u\\ \\dx=\dfrac{1}{2}\cdot \dfrac{1}{\cos ^2 u}du

Then

SA=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx=2\pi \int\limits^{\arctan(4)}_0 \dfrac{1}{4}\tan^2u\sqrt{1+\tan^2u} \, \dfrac{1}{2}\dfrac{1}{\cos^2u}du=\\ \\=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0 \tan^2u\sec^3udu=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0(\sec^3u+\sec^5u)du

Now

\int\limits^{\arctan(4)}_0 \sec^3udu=2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17})\\ \\ \int\limits^{\arctan(4)}_0 \sec^5udu=\dfrac{1}{8}(-(2\sqrt{17}+\dfrac{1}{2}\ln(4+\sqrt{17})))+17\sqrt{17}+\dfrac{3}{4}(2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17}))

Hence,

SA=\pi \dfrac{-\ln(4+\sqrt{17})+132\sqrt{17}}{32}

3 0
3 years ago
Whats the perimeter and area of this shape?
stich3 [128]

Answer:

<u>60+14.35=88.27</u>

Step-by-step explanation:

5x12 for the rectangle on the right, then for the circle, using the formula A=πr², I get 28.27, which you divide by 2 because you only need half of the circle, and you get 88.27. I calculated the radius by subtracting 12-6 and then dividing that in half because the radius is half of the distance to the other end of the circle. Then you get the radius of 3, then plug it into the formula to get π(3)², which is just 3.14(9), and you get 28.27.

8 0
3 years ago
Read 2 more answers
What is the answer to this please
Alex_Xolod [135]
Domain: x≤5 (notice the closed dot on the right and the arrow on the left)
Range: y≤2 (notice the closed dot on the right and the arrow on the left)

The arrow means it keeps going infinitely. The closed dot means it stops there but is inclusive of that value.
3 0
3 years ago
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