If your food cost is 30% what percent is your profit?

What is the length (magnitude) of the vector (5 -2) a. √29 b. 5√5 c. 5 d.√2

malfutka [58]

Answer:

a. √29

Step-by-step explanation:

The formula for the magnitude of a vector is magnitude = sqrt(x^2 + y^2).

For vector (5, -2):

magnitude = sqrt(5^2 + -2^2)

magnitude = sqrt(25 + 4)

magnitude = sqrt(29)

Therefore, the answer is √29.

Hope this helped :D

8 0

2 years ago

A company designs a logo using a kite figure around the letter t. The logo is 12 centimeters wide and 16 centimeters tall. What

Temka [501]

Answer:

96 sq. cm.

Step-by-step explanation:

A "kite" has 2 diagonals, which are the "width" and "height" of the kite.

Using diagonals, the area of a kite is given by $A=\frac{pq}{2}$

Where

A is the area

p,q are the width and height, respectively

From the problem given, p is 12 and q is 16, so the area is:

$A=\frac{pq}{2}\\A=\frac{(12)(16)}{2}\\A=96$

Thus, the area is 96 sq. cm

5 0

2 years ago

Read 2 more answers

A local grocery store is running a marketing promotion on social media. They are randomly choosing a winner from the entrants th

AlladinOne [14]

Using it's concept, it is found that the odds that the winner shops in the store 4 or more times a week are given by: 9:41.

<h3>What is the odd of an event?</h3>

It is given by the number of desired outcomes divided by the number of non-desired outcomes.

Researching the problem on the internet, it is found that 18% of the winners shop in the store 4 or more times a week, while 82% do not, hence:

18:82 = 9:41

The odds that the winner shops in the store 4 or more times a week are given by: 9:41.

More can be learned about odds at brainly.com/question/25683609

3 0

1 year ago

From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th

wel

Answer:

$\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}$

Step-by-step explanation:

The width of a square is its side length.

The width of a circle is its diameter.

Therefore, the largest possible circle that can be cut out from a square is a circle whose diameter is equal in length to the side length of the square.

Formulas

$\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}$

$\sf \textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}$

$\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}$

If the diameter is equal to the side length of the square, then:
$\implies \sf r=\dfrac{1}{2}s$

Therefore:

$\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}$