Answer:
show that the three sets of corresponding sides are in proportion. If the three sets of corresponding sides of two triangles are in proportion, the triangles are similar.
Step-by-step explanation:
Answer:
Mmmm let me think.mmmm oh a coW Moo
Answer:

Step-by-step explanation:

![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Answer:
all in all it's y=x
Step-by-step explanation:
A (4,1); B (0,-2)
G=delta y
--------
delta x
1-(-2)
-------
4-0
3/4=G
3/4=y-1/x-4
4 (y-1)=3 (x-4)
4y-4=3x-12
4y=3x+4-12
y=3/4x-3
Answer:

Step-by-step explanation:
<h3><u>Given that:</u></h3>
Exterior angle of L = 5x + 12
M = 3x - 2
N = 50
<h3><u>Statement:</u></h3>
- Exterior angle is equal to the sum of non-adjacent interior angles.
So, the exterior angle that is adjacent to L is equal to the sum of non-adjacent sides (M and N) of the triangle.
Here,
Exterior angle of L = M + N
5x + 12 = 3x - 2 + 50
5x + 12 = 3x + 48
Subtract 12 to both sides
5x = 3x + 48 - 12
5x - 3x = 36
2x = 36
Divide 2 to both sides
x = 18
So,
<h3><u>Measure of angle M:</u></h3>
= 3x - 2
= 3 (18) - 2
= 54 - 2
= 52°
Now,
<h3><u>Measure of angle L:</u></h3>
<u>We know that,</u>
- Sum of all the interior angles of triangle is 180 degrees.
L + M + N = 180°
L + 52 + 50 = 180
L + 102 = 180
Subtract 102 to both sides
L = 180 - 102
L = 78°
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)